A 68.0 Kg tightrope walker stands at the center of a rope. The rope supports are 10 m apart and the rope sags 8.00 degrees at ea
1 answer:
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Answer:
0.75
Explanation:
= 1.5
1.5 × ½ = sin(i)
The work done to stretch the spring will be 112 J.
<h3>What is spring force?</h3>The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is
F = kx
The given data in the problem is;
F is the spring force =?
K is the spring constant= 8.5 N/m
x is the length by which spring got stretched = 1.2m
The work is done to stretch the spring is;
To learn more about the spring force refer to the link;
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