Answer: 90 m/s
Explanation:
Given
mass of racecar 
velocity of racecar 
mass of still honeybadger 
after collision race car is traveling at a speed of 
conserving linear momentum
![Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}]](https://tex.z-dn.net/?f=Mu%2Bm%5Ctimes0%3DMv_1%2B%20mv_2%5Cquad%5Bv_2%3D%5Ctext%7Bvelocity%20of%20honeybadger%20after%20colllision%7D%5D)


Answer:
The frequency of the phonograph record is 0.2 Hz
Explanation:
The frequency of an object moving in uniform circular motion is the number of completed cycles the object makes in a specified time period
The given parameters of the phonograph record are;
The radius of the record = 0.15 m
The number of times the phonograph record rotates, n = 18 times
The time it takes the phonograph record to rotate the 18 times, t = 90 seconds
The frequency of the phonograph record, f = (The number of times the phonograph record rotates) ÷ (The time it takes the phonograph record to rotate the 18 times)
∴ The frequency of the phonograph record, f = n/t = 18/(90 s) = 0.2 Hz
The frequency of the phonograph record = 0.2 Hz.
Answer:
B. Acidic
Explanation:
Neutral an Basic solutions wouldn't create any reaction
Answer:
there are no pictures attached.
Answer:
The percentage power lost in the transmission line if the voltage not stepped up is 50%.
Explanation:
Given that,
Current = 60 A
Voltage = 120 V
Resistance = 1.0 ohm
We need to calculate the power
Using formula of power

Where,I =current
V = voltage
Put the value into the formula


We need to calculate the percentage power lost in the transmission line
If the voltage is not stepped up
Then, the power loss

Put the value into the formula


The percentage power loss P''


Hence, The percentage power lost in the transmission line if the voltage not stepped up is 50%.