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Morgarella [4.7K]
3 years ago
14

What choice is equivalent to the quotient when x>0? [Photo attached]

Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0

Answer:

\Large \boxed{\bold{D.} \  \frac{5 \sqrt{x} } {4}}

Step-by-step explanation:

\displaystyle \frac{\sqrt{50x^3 }}{\sqrt{32x^2 } }

Distributing the square root.

\displaystyle \frac{\sqrt{50} \sqrt{x^3 } } {\sqrt{32} \sqrt{x^2  }}

Simplifying the expression.

\displaystyle \frac{5 \cdot \sqrt{2} \cdot  x \cdot  \sqrt{x} } {4 \cdot \sqrt{2} \cdot x}

Cancelling the square root of 2 and x on both the numerator and the denominator.

\displaystyle \frac{5 \cdot \sqrt{x} } {4}

MakcuM [25]3 years ago
3 0

Answer:

D)  5√x / 4

Step-by-step explanation:

√50x^3 / √32x^2

= (5x√2x) / (4x√2)

= 5/4 √(2x/2)

= 5/4 (√x)

= 5√x / 4

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Equation to find three consecutive odd integers whose sum is 3
KiRa [710]

The equation computed shows that the numbers will be 9, 11 and 13.

<h3>How to illustrate the information?</h3>

Let the numbers be:

First number = x

Second number = x + 2,

Third number = x + 4.

Total of the numbers = 33

The equation will be:

= first + second + third number

x + x + 2 + x + 4 = 33

3x + 6 = 33

Collect like terms

3x = 33 - 6

3x = 27.

Divide both side by 3

3x/3 = 27/3

x = 9

First number = x = 9

Second number = x + 2 = 9 + 2 = 11

Third number = x + 4. = 9 + 4 = 13

The numbers will be 9, 11, and 13.

Learn more about equations on:

brainly.com/question/2972832

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Illustrate the equation to find three consecutive odd integers whose sum is 33.

8 0
2 years ago
Use Pascal’s Triangle to determine the fifth term of the expansion of (x + 3)7
ValentinkaMS [17]

Answer:

2835x^5.

Step-by-step explanation:

By Binomial Theorem, T(r+1) = nCr * a^(r+1) * b^r.

Term 5 = 7C4 * x^5 * 3^4

= 35 * x^5 * 3^4

= 2835x^5.

7 0
3 years ago
NEED HELP ASAP WILL GIVE BRAINLIEST
Zepler [3.9K]

Answer:

C

Step-by-step explanation:

I used the formula. it took a long but i got it! Brainly pls!

7 0
2 years ago
In the city where sonya lives, it rains and average of 8.05 centimeters each month last year.About how many centimeters of rain
erik [133]
In total it rained 96.6cm that year but on average it rained 100cm that year.
You would multiply 8.05 times the #of momths which is twelve.
7 0
3 years ago
RIGHT ANSWER I'LL GIVE BRAINLIES
Alex_Xolod [135]
I really hope this is right but 6?
7 0
2 years ago
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