What is the balanced equation of Na2S+CuSO4=CuS+Na2SO4?
1 answer:
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Answer:
The conversion factor is 14.79 mL/Tbsp.
Explanation:
To do an unity conversiton, we can make a factor by a ratio transformation:
So, the conversion factor is 14.79 mL/Tbsp and 3 Tbsp has 44.37 mL.
pH of 0.048 M HClO is 4.35.
<u>Explanation:</u>
HClO is a weak acid and it is dissociated as,
HClO ⇄ H⁺ + ClO⁻
We can write the equilibrium expression as,
Ka =
Ka = 4.0 × 10⁻⁸ M
4.0 × 10⁻⁸ M =
Now we can find x by rewriting the equation as,
x² = 4.0 × 10⁻⁸ × 0.048
= 1.92 × 10⁻⁹
Taking sqrt on both sides, we will get,
x = [H⁺] = 4.38 × 10⁻⁵
pH = -log₁₀[H⁺]
= - log₁₀[ 4.38 × 10⁻⁵]
= 4.35