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anzhelika [568]
3 years ago
8

If an object is floating in water does that mean that the weight is zero?

Physics
1 answer:
gayaneshka [121]3 years ago
8 0
Nope. It means that the density of the object is less than the density of the water it's in, making it float. Conversely, if the density of an object is greater than the density of the water it's in, then the object will sink. :) 
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675 km equals how much cm ?
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KHDMDCM.
Now go from Kilometer to Centimeter: 5.
Move the decimal 5 places to the right: 67,500,000 centimeters.
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Which of the following statements is true about magnetic fields. Magnets and magnetic fields were only just discovered in the la
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Answer:

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Give a flow chart of how the inlet and exhaust valve operate in the internal combustion engine of a tractor.
abruzzese [7]

Flow chart of a system is a diagrammatic representation of how that system performs it's functions.

<h3>The flow chart of internal combustion engine</h3>

The flow chart of internal combustion engine is the diagrammatic representation of how the engine works.

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The exhaust valve of the engine is the allows for the outflow of used gases from the engine.

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PLZ answer asp The image shows the combustion of methane. Which equation represents this chemical reaction?
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Simple question please help! A ball is thrown 19.0 m/s at an angle of 40.0º with the horizontal. Assume the ball is thrown at gr
d1i1m1o1n [39]

a. 1.51 s

In this part of the problem, we are only interested in the horizontal motion of the ball. Along the horizontal direction, the motion of the ball is a uniform motion with constant velocity, which is equal to the horizontal component of the initial velocity:

v_x = v_0 cos \theta = (19.0 m/s)(cos 40^{\circ})=14.6 m/s

So, the ball travels horizontally at a speed of 14.6 m/s; in order to cover the distance of d = 22.0 m that separates it from the wall, the time need is

t=\frac{d}{v_x}=\frac{22.0 m}{14.6 m/s}=1.51 s

b. 7.25 m

We now know that the ball takes 1.51 s to hit the wall, 22.0 away. Now we have to analyze the vertical motion of the ball, which is an accelerated motion with constant acceleration g =9.8 m/s^2 towards the ground (acceleration due to gravity).

The initial vertical velocity is

v_{y0}=v_0 sin \theta=(19.0 m/s)(sin 40^{\circ})=12.2 m/s

The vertical position of the ball at time t is given by the equation

y(t)=v_{0y} t -\frac{1}{2}gt^2

We know that the ball hits the wall at t=1.51 s, so if we substitute this value into the previous formula, we find at what height y the ball hits the wall:

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7 0
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