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GuDViN [60]
3 years ago
6

Which of the following terms is correct when talking about energy?

Physics
2 answers:
vlabodo [156]3 years ago
5 0

Answer:

C. Converting Energy

Explanation:

Hope this helped, Have a Wonderful Day!!

Ivahew [28]3 years ago
3 0

Answer:  I think its B

Producing energy

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In the eastern US, hurricanesusually form over the warm waters of the Caribbean Sea and travel north. When they are over the col
garik1379 [7]

Answer:

Less powerful

Explanation:

Hurricanes rely on warm water. It sucks heat energy from the water to use for fuel. Warmer water means more moisture, which also mean a bigger and/or stronger hurricane. The North Atlantic is definitely much colder than the Caribbean so the hurricane will not have much fuel.

Have a great day!

8 0
3 years ago
This picture shows some fortified cereal in a bowl.
ikadub [295]
Cereals are usually fortified with three most common minerals and vitamins which are:
1- Iron
2- Vitamin D
3- Vitamin B-12

Comparing the above to the given choices, we will find that the best answer is:
b. iron
3 0
4 years ago
A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.60 m/s. How
kirill115 [55]

Answer:

Efriction = 768.23 [kJ]

Explanation:

In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.

We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.

The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.

E_{pot}-E_{friction}=E_{kin}

where:

E_{pot}=m*g*h\\E_{kin}=\frac{1}{2}*m*v^{2}

m = mass = 56 [kg]

h = elevation = 1400 [m]

v = velocity = 5.6 [m/s]

(56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]

4 0
3 years ago
In a playground, there is a small merry-go-round of radius 1.20 m and mass 160 kg. Its radius of gyration is 91.0 cm. (Radius of
aksik [14]

Answer:

a) 145.6kgm^2

b) 158.4kg-m^2/s

c) 0.76rads/s

Explanation:

Complete qestion: a) the rotational inertia of the merry-go-round about its axis of rotation 

(b) the magnitude of the angular momentum of the child, while running, about the axis of rotation of the merry-go-round and

(c) the angular speed of the merry-go-round and child after the child has jumped on.

a) From I = MK^2

I = (160Kg)(0.91m)^2

I = 145.6kgm^2

b) The magnitude of the angular momentum is given by:

L= r × p The raduis and momentum are perpendicular.

L = r × mc

L = (1.20m)(44.0kg)(3.0m/s)

L = 158.4kg-m^2/s

c) The total moment of inertia comprises of the merry- go - round and the child. the angular speed is given by:

L = Iw

158.4kgm^2/s = [145kgm^2 + ( 44.0kg)(1.20)^2]

w = 158.6/208.96

w = 0.76rad/s

7 0
3 years ago
Bearing in mind that a sound reflects off an object if the object is larger than the wavelength of the sound, calculate the wave
grandymaker [24]

Answer:

mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

Explanation:

The human ear can detect sound in the range of 20 to 20000hz, we are asked to find the mid-range wavelength of the ear at f = 10000 Hz

let's use the relationship between wave speed, wavelength and frequency

           v = λ f

           λ= v / f

           λ = 343/10000

           λ = 3.43 10⁻² m

the sound range of a bat is between 25 10³ Hz and 100 10³ Hz, they also ask for the wavelength in the middle range

         

          f = (100 10³ + 25 10³) / 2

          f = 62.5 10³ Hz

          λ = 343 / 62.5 10³

          λ = 5.5 10⁻³ m

Therefore the size of the object that a bat can detect is much smaller than the size that a human can detect, therefore the bat is capable of detecting insects, but humans.

The mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

4 0
3 years ago
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