Which of the following terms is correct when talking about energy?
2 answers:
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We are given volume of gasoline = 15.58 L and
Density = 0.74 g/mL.
Density is given in grams(g) per milliliter (mL). So, we need to convert given volume in mL also.
We know, 1 litre = 1000 milliliters
Therefore, 15.58 L = 15.58 * 1000 mL = 15580 mL
We could rewrite,
Volume of gasoline = 15580 mL.
Formula for density is..
Density (ρ)=
Plugging values in formula,
0.74 g/mL =
Muliplying both sides by 15580.
11529.2g = mass.
Therefore, 11529.2g grams does 15.58 L of gasoline weigh.
Answer:
Direction 1: Force is Non-zero and Not- constant
Direction 2: Force is Non-zero but constant
Explanation:
Given:
The picture of the map is attached. ( Missing from the question ).
Find:
The effect of force as it travels along each direction.
Solution:
- We know the relationship between change in potential and the force acting on the charge particle is given by:
F = - q*dV/ dr
Where,
q : Charge of the particle
V : Volt potential
dV/dr : Potential difference along a direction.
Direction 1:
- The color code of the map changes as the particle moves along this direction. Each color code represents a potential difference. So as the particle moves between different potential difference then according to the relationship given above The force varies along varies as particle moves from one color to another. Hence, a non zero force but not constant.
Direction 2:
- In the direction 2, the charged particle moves along the same color. The potential difference for each color is constant. Hence, according to the relationship of potential difference and force. If potential difference is constant then the Electrostatic Force on the charge is also constant. Hence, Force is non-zero and constant.
Answer:
dJ = 1.7 m
Explanation:
The Equation of the Balancing the moments in the center of the seesaw is like this:
∑Mo = 0
Mo = F*d
Where:
∑Mo : Algebraic sum of moments in the center(o) of the balance
Mo : moment in the o point ( N*m)
F : Force ( N)
d : distancia of the force to the the o point ( N*m)
Data
mA = 60 kg : mass of the Anna
mJ = 70 kg : mass of theJon
dA = 2 m : Distance from Anna to the center of the seesaw
g: acceleration due to gravity
Calculation of the distance from Jon to the center of the seesaw (dJ)
∑Mo = 0 WA : Ana's weight , WJ : Jon's weight
W = m*g
(WA)(dA) - (WJ) (dJ) = 0
(mA*g)(dA) - (mJ*g)(dJ) = 0
We divide by g the equation:
(mA)(dA) - (mJ)(dJ)= 0
(mA)(dA) = (mJ)(dJ)
dJ = 1.7 m