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torisob [31]
3 years ago
13

WILL MARK BRAINLIEST. Look at the circuit below. What is the voltage between points C and D?

Physics
2 answers:
lianna [129]3 years ago
7 0

The hard way:

-- The total resistance in the series circuit is 120 ohms.

-- The current in the circuit is (voltage)/(resistance) = 3/60 = 0.025 A

-- The resistance between C and D is 60 ohms.

-- The voltage across a resistance is (current) x (resistance) = (0.025 x 60) = <em>1.5 volts. </em>(C)

<em>=================================</em>

The easy way:

-- In a series circuit, the total voltage of the power source divides among the circuit's components in proportion to their resistances.

-- Since the bulbs have equal resistances, each one will have 1/2 of the battery voltage across it.

-- (1/2) of (3 volts) = <em>1.5 volts</em> (C)

elena-s [515]3 years ago
6 0

Since two identical bulbs are connected in this circuit in series combination

So here same current will flow into the circuit

So here we can say

V = V_1 + V_2

V = 3 volts

also we know that

V_1 = iR_1

V_2 = iR_2

also it is given that bulbs are identical so we have

V_1 = V_2

as we have

R_1 = R_2

so now we can say

V = 2V_{CD}

3 = 2V_{CD}

V_{CD} = 1.5 Volts

so here voltage across C and D is 1.5 volts

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