I believe the answer is 7.24 kJ.
From the equation ΔE = dW + dQ; where W is the work done on/by the system and Q is the heat the system absorbs/loses.
Therefore; ΔE = 72.4 kJ since the system has bot done any p-v work (dV= zero) and has absorbed heat.
Answer:
Explanation:
Circle motion
Weight=4lb
Radius=3ft
Velocity Vb= 6ft/s
Velocity Vr=2ft/s
Velocity Vo=12
V2=√Vo²+Vr²
12=√Vo²+2²
Square both side
144=Vo²+4
Vo²=140
Vo=11.83ft/s
Applying conservation of angular momentum
Ha1=Hb2
MbVbr1=MbVor2
r2=Vbr1/Vo
r2=6×3/11.83
r2=1.52ft
The require time is written as.
∆r=Vrt
t=∆r/Vr
t=r1-r2/Vr
t=3-1.52/2
t=0.74sec
The chemical bonds alow it to pass to the other object.
Answer:
Current will decrease.
Explanation:
When we increase the number of stepping in transformer, the voltage will increase as its is directly proportional to the number of turn of stepping. Thus as the voltage will increase, current will decrease. As per the equation of ideal transformer, E1 / E2 = I2 / I1
E1 and E2 are the voltages in primary and secondary winding and I1 and I2 are the current.
As the number of turns will be increased more inevitable losses will be generated that dissipates heat thus warming the primary.
Though the conservation of energy is obeyed but losses occur in this scenario hence step-up transformers cannot be used to create free energy.
Answer:
Explanation:
Given:
Initial velocity, u = 0 m/s (at rest)
Final velocity, v = 22 m/s
Time, t = 9 s
Diameter, d = 58 cm
Radius, r = 0.29 m
Using equation of motion,
v = u + at
a = (22 - 0)/9
= 2.44 m/s^2
v^2 = u^2 + 2a × S
S = (22^2 - 0^2)/2 × 2.44
= 99.02 m
S = r × theta
Theta = 99.02/0.29
= 341.44 °
1 rev = 360°
341.44°,
= 341.44/360
= 0.948 rev
= 0.95 rev
B.
Final angular speed, wf = v/r
= 22/0.29
= 75.86 rad/s
