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zysi [14]
3 years ago
10

Please help willing to give brainliest

Physics
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

sound water because sound is the most important electronic wave for water

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You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs
Fudgin [204]

Answer:

3.6m

Explanation:

if you are at a building that is 46m above the ground, and the professor is 1.80m, the egg must fall:

46m - 1.80m = 44.2m

the egg must fall for 44.2m to land on the head of the professor.

Now, how many time this takes?

we have to use the following free fall equation:

h=v_{0}t+\frac{1}{2}gt^2

where h is the height, v_{0} is the initial velocity, in this case v_{0}=0. g is the acceleration of gravity: g=9.81m/s and t is time, thus:

h=\frac{1}{2}gt^2

clearing for time:

2h=gt^2\\\frac{2h}{g}=t^2\\\sqrt{\frac{2h}{g}} =t

we know that the egg has to fall for 44.2m, so h=44.2, and g=9.81m/s, so we the time is:

t=\sqrt{\frac{2(44.2m)}{9.8m/s^2} }=\sqrt{\frac{88.4m}{9.81m/s^2} } =\sqrt{9.011s^2}= 3.002s

Finally, if the professor has a speed of v=1.2m/s, it has to be at a distance:

d=vt

and t=3.002s:

d=(1.2m/s)(3.002s)=3.6m

so the answer is the professor has to be 3.6m far from the building when you release the egg

7 0
3 years ago
If the battery of your phone can provide 2 mA of current to your phone and holds a charge of 130 C, how long will it take a full
Naya [18.7K]

Answer: 65000 seconds

Explanation:

Given that,

Current (I) = 2 mA

(Since 1 mA = 1 x 10^-3A

2 mA = 2 x 10^-3A)

Charge (Q) = 130 C

Time taken for a fully charged phone to die (T) = ?

Recall that the charge is the product of current and time taken.

i.e Q = I x T

130C = 2 x 10^-3A x T

T = 130C / (2 x 10^-3A)

T = 65000 seconds (time will be in seconds because seconds is the unit of time)

Thus, it will take a fully charged phone 65000 seconds to die

5 0
4 years ago
Nasa has developed deep-space 1 (ds-1), a spacecraft that is scheduled to rendezvous with the asteroid named 1992 kd (which orbi
andrezito [222]
I can't give an exact number if the original velocity of ds-1 is not given. In that case, the final answer should just be in terms of an equation. Let's denote the original velocity to be v₀ and the days to be d.

Part a.)
v = v₀ + 9.23d
3440 = v₀ + 9.23d
9.23d = 3,440 - v₀
d = (3,440 - v₀)/9.23

Part b.)

The acceleration is the change in velocity per unit time. So, that would be 9.23 m/s per day. Since there are 86,400 s in a day:

a = 9.23 m/s / day * 1 day/ 86,400 s
a = 0.0001068 m/s²
6 0
3 years ago
How does 'g' vary from place to place?​
r-ruslan [8.4K]

Explanation:

The acceleration g varies by about 1/2 of 1 percent with position on Earth's surface, from about 9.78 metres per second per second at the Equator to approximately 9.83 metres per second per second at the poles.

8 0
3 years ago
Why is it necessary to enrich the soil?
enyata [817]
Plants rely on proper soil conditions to give them nutrients and minerals. 
5 0
4 years ago
Read 2 more answers
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