Question

you reach into a bag of coins and withdraw two coins without replacement. what is the probability you will withdraw a nickel and then a dime if the bag has 5 pennies, ten nickels and four dimes?

Answer 1

There is about a 11.695% chance that that would happen.

Answer 2

Answer: The answer is 11.69%.

Step-by-step explanation: Given that there is a bag full of coins, in which

Number of pennies = 5,

number of nickels = 10

and number of dimes = 4.

Therefore, total number of coins in the bag = 5 + 10 + 4 =19.

According to the question, first we draw a nickel, so probability will be

$p_1=\dfrac{10}{19},$

and then, without replacement, we draw a dime, so probability will be

$p_2=\dfrac{4}{18}.$

So, the required probability will be

$p=p_1\times p_2=\dfrac{10}{19}\times \dfrac{4}{18}=0.1169=11.69\%.$

Thus, the probability is 11.69%.