Answer:
the atoms of the original substances gain, lose and even share their very own electrons. write the symbols of the elements that form the compound. Write down the valency, and lastly go over valencies. This is all I got so far. I hope this helps
Explanation:
1.) <span>2Na(aq)+2H2O(l)→2NaOH(aq)+H2(g),
Na is oxidizing agent and H is reducing agent.
2.) </span><span>C(s)+O2(g)→CO2(g)
C is an oxidizing agent
3.) </span><span>2MnO−4(aq)+5SO2(g)+2H2O(l)→2Mn2+(aq)+5SO2−4(aq)+4H+(aq)
Mn is reducing agent and S is oxidizing agent.</span>
Answer:
Daniel Bernoulli
Explanation:
He made a book with laid the basics down for kinetic theory
Answer:
3-bromo-4-ethyl-2,2,5-trimethyloctane.
Explanation:
You need to find the longest carbon chain. In this molecule, the longest carbon chain goes straight across and contains 8 carbons (oct-). There are no double or triple bonds so its octane.
Number the carbon chain from 1-8, starting at the end that is closest to a group. The left side is closest to a group so start from there.
On carbon 2, there are two methyl groups. On carbon 5, there is one methyl group. When naming, it will be 2,2,5-trimethyl.
On carbon 3, there is one bromine group. When naming, it will be 3-bromo.
On carbon 4, there is one ethyl group. When naming, it will be 4-ethyl.
Order the names of the groups alphabetically in front of octane.
The name of the compound is 3-bromo-4-ethyl-2,2,5-trimethyloctane.
