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3 years ago

Why is si system better than CGS system

Physics

2 answers:

jok3333 [9.3K]3 years ago

8 0

Answer:

The SI system, for this reason, is also called the MKS system. CGS system: On the other side or the second self-consistent system uses centimetres, grams and seconds for length, mass and time.

Explanation:

Lubov Fominskaja [6]3 years ago

8 0

SI unit is same everywhere however in cgs unit there are different units of measurement

SI unit is adopted internationally and the units are fixed and do not change at any place

hope that helps !

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torisob [31]

Answer:

a) $T_{min} = 80\,s$

Explanation:

a) Let consider that disk accelerates and decelerates at constant rate. The expression for angular acceleration and deceleration are, respectively:

Acceleration

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Deceleration

$\alpha_{2} = -\frac{\omega_{max}^{2}}{2\cdot (400\,rad)}$

Since angular acceleration and deceleration have same magnitude but opposite sign. Let is find the maximum allowed angular speed from maximum allowed centripetal acceleration:

$a_{r,max} = \omega_{max}^{2}\cdot r$

$\omega_{max} = \sqrt{\frac{a_{r,max}}{r} }$

$\omega_{max} = \sqrt{\frac{100\,\frac{m}{s^{2}} }{0.25\,m} }$

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Maximum magnitude of acceleration/deceleration is:

$\alpha = 0.5\,\frac{rad}{s^{2}}$

The least time require for rotation is:

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$T_{min} = 80\,s$

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3 years ago

What would be the kinetic energy k2q of charge 2q at a very large distance from the other charges? express your answer in terms

Pavlova-9 [17]

Answer:

$K_{2q}=\frac{7.76kq^2}{d}$

Explanation:

At the corner of the square, the potential energy of interaction of other charges with the charge 2q is given by $U_{2q}$

$U_{2q,i}=k\frac{(2q)(q)}{d}+k\frac{(2q)(5q)}{d}+k\frac{(2q)(-3q)}{\sqrt{2}d}=\frac{7.76 kq^2}{d}$

Also, since $K_{2q,i}=0$

The initial energy of the system is given by;

$E_i=U_{2q ,i}+K_{2q,i}=\frac{7.76kq^2}{d}+0=\frac{7.76kq^2}{d}$

Since $U_{2q,f}=0$

, the final energy of the system is obtained by

$E_f=U_{2q ,f}+K_{2q,f}=0+K_{2q,f}$

From the law of conservation of energy, $E_i=E_f$

Therefore, $K_{2q}=\frac{7.76kq^2}{d}$

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