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ASHA 777 [7]
3 years ago
9

Jimmy cell phone plan has been a base charge of $50 per month with an additional charge of 65 cents per app downloaded. Lisa cel

l phone plan has a base charge of $55 per month with an additional charge of 40 cents per app downloaded. How many apps will Jimmy and Lisa need to download for the bills to be the same?
Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

20

Step-by-step explanation:

We write what we know.

Jimmy

$50/mo   app 65¢ or .65

Lisa

$55/mo   app 40¢ or .40

a = number of apps

The difference will come from the number of apps, a.

We need them to equal each other so let's write an equation.

$50 + .65a = $55 + .40a

We need to solve for a.

$50 + .65a = $55 + .40a     subtract $50 for each side.

$50 - $50 + .65a = $55 - $50 + .40a

.65a = $55 - $50 + .40a

.65a = $5 + .40a     subtract .40a from each side

.65a - .40a = $5 + .40a - .40a

.65a - .40a = $5

.25a = $5   Divide each side by .25

.25a/.25 = $5/.25

a = $5/.25

a = 20

So Jimmy and Lisa need to download 20 apps for their bill to be the same.

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\frac{v}{\sqrt{\frac{m\cdot g}{b} } }=\tan \left[-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)\right]

v = \sqrt{\frac{m\cdot g}{b} } \left [\frac{\tan \left(-\frac{2\cdot b \cdot t}{m}  \right)+ \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)}{1 - \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)\cdot \tan \left(-\frac{2\cdot b \cdot t}{m}  \right) }\right]

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