Answer: 2.28%
Step-by-step explanation:
Given: An airport find that at the present time, the mean noise level is 103 decibels and the standard deviation is 5.4 decibels.
The distribution of noise levels(x) for all jets during takeoff over the neighborhood has a normal distribution.
The probability that jets have a noise level less than 92.2 decibels when taking off over this neighborhood will be :-

Hence, the percent of these jets have a noise level less than 92.2 decibels when taking off over this neighborhood = 2.28%
Answer:
it's 100
Step-by-step explanation:
70000
0000
600
80
1
I don't know if you understand
Answer:
a) x = -10
b) x = 7
Step-by-step explanation:
a)
2(x + 3) = x - 4
2x + 6 = x - 4
2x - x = -4 - 6
x = -10
b)
4(5x - 2) = 2(9x + 3)
20x - 8 = 18x + 6
20x - 18x = 6 + 8
2x = 14
x = 7
Answer:
9 ÷ 1504 = 0 R 9
0.00598404255
Step-by-step explanation:
Shown above is remainder form and decimal form...