All categories

3 years ago

The x intercepts of a parabola are (6,0) and (-2,0) determine the x coordinate of the vertex

1 answer:

4 0

This means that (x-6)(x+2) = f(x) is the equation for the parabola due to that if you plug these in, when x=6 and x=-2 then y=0. Expanding it, we get
x^2+2x-6x-12=x^2-4x-12. Since the x coordinate of the vertex is -b/2a, it's 4/2=2

You might be interested in

Cuantos nanómetros soporta el cuerpo

WITCHER [35]

Step-by-step explanation:

1 mn diameter self assembled

nature inspired structure

6 0

3 years ago

Read 2 more answers

A hemispherical tank is filled with water and has a diameter of 19 feet. If water

pogonyaev

We know that the volume of a sphere is:

where

is the radius;

we need half of this, so we use:

261.8

giving a total weight of water of:

261.8

⋅

62.4

336

pounds

6 0

3 years ago

Read 2 more answers

Expand why you would make one of the addends a tens number when solving an addition problem.

MaRussiya [10]

It makes it easier to solve

4 0

3 years ago

Help me plzzzzzzzzzzzzzzzzzzz

lubasha [3.4K]

Answer:

Step-by-step explanation:

irdk sorry if its wrong :(

5 0

3 years ago

A random sample of 21 observations is used to estimate the population mean. The sample mean and the sample standard deviation ar

stepladder [879]

Answer:

a. CI=[128.79,146.41]

b. CI=[122.81,152.39]

c. As the confidence level increases, the interval becomes wider.

Step-by-step explanation:

a. -Given the sample mean is 137.6 and the standard deviation is 20.60.

-The confidence intervals can be constructed using the formula;

$\bar X\pm \ z\frac{s}{\sqrt{n}},$

where:

$s$ is the sample standard deviation
$z$ is the s value of the desired confidence interval

we then calculate our confidence interval as:

$\bar X\pm z\frac{s}{\sqrt{n}}\\\\=137.60\pm z_{0.05/2}\times\frac{20.60}{\sqrt{21}}\\\\=137.60\pm1.960\times \frac{20.60}{\sqrt{21}}\\\\=137.60\pm8.8108\\\\\\=[128.789,146.411]$

Hence, the 95% confidence interval is between 128.79 and 146.41

b. -Given the sample mean is 137.6 and the standard deviation is 20.60.

-The confidence intervals can be constructed using the formula in a above;

$\bar X\pm z\frac{s}{\sqrt{n}}\\\\=137.60\pm z_{0.01/2}\times\frac{20.60}{\sqrt{21}}\\\\=137.60\pm3.291\times \frac{20.60}{\sqrt{21}}\\\\=137.60\pm 14.7940\\\\\\=[122.806,152.394]$

Hence, the variable's 99% confidence interval is between 122.81 and 152.39

c. -Increasing the confidence has an increasing effect on the margin of error.

-Since, the sample size is particularly small, a wider confidence interval is necessary to increase the margin of error.

-The 99% Confidence interval is the most appropriate to use in such a case.

7 0

4 years ago