Question

Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Water is being drained from the first pool at a rate of 33 liters per minute. Water is being drained from the second pool at a rate of 43 liters per minute. Let x be the number of minutes water has been drained. (a) For each pool, write an expression for the amount of water in the pool after x minutes.
Amount of water in the first pool (in liters) =

Amount of water in the second pool (in liters) =

(b) Write an equation to show when the two pools would have the same amount of water.​

Answer 1

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Reasoning in the same way:

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)  Now want to know when the two pools would have the same amount of water.  If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes