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2 years ago

13

A scale drawing of a school bus has a scale of inch to 5 feet. If the length of the school bus is inches on the scale drawing,

what is the actual length of the bus? Explain or show your reasoning.

1 answer:

ANTONII [103]2 years ago

7 0

You forgot the 1/2 Inches in that,

but the answer is 45 feet.

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A mass weighting 64 pounds, attached to the end of a spring and stretches the spring 0.32 foot. There is no damping and no exter

scoundrel [369]

Answer:

Step-by-step explanation:

Check attachment for solution

<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> pdf </span>

8 0

3 years ago

Your friend has built the skate board ramp shown in the figure with sides of 16 in., 63 in., and 65 in. that he claims has dispr

nexus9112 [7]

The friend is wrong - According to the Pythagorean Theorm, if c is the hypotenuse and a and b are opposite sides then c^{2} = a^{2} + b^{2}
if c=65 inches, a=16 inches and b = 63 inches, then
65^{2} =16 ^{2} + 63^{2}
right hand side of the equation = 256 + 3969 = 4225
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So we see, left hand side = right hand side
Hence the theorm is proved.

5 0

3 years ago

Select the correct answer.

mestny [16]

Answer:

B.

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4 0

3 years ago

Use a paragraph, flow chart, or two-column proof to prove the angle congruency. Given: ∠ CXY ≅ ∠ BXY

Llana [10]

Answer:

See explanation

Step-by-step explanation:

Consider triangles CAX and BAX. In these triangles,

$\overline{AC}\cong \overline{AB}$ - given
$\angle CAX\cong \angle BAX$ - given
$\overline{AX}\cong \overline{AX}$ - reflexive property

By SAS postulate, $\triangle CAX\cong \triangle BAX$

Congruent triangles have conruent corresponding parts. So,

$\overline{CX}\cong \overline{BX}$

Consider triangles CXY and BXY. In these triangles,

$\overline{CX}\cong \overline{BX}$ - proven
$\angle CXY\cong \angle BXY$ - given
$\overline{XY}\cong \overline{XY}$ - reflexive property

By SAS postulate, $\triangle CXY\cong \triangle BXY$

Congruent triangles have conruent corresponding parts. So,

$\angle XCY\cong \angle XBY$

5 0

3 years ago

I REALLY NEED HELP PLEASE!

zhuklara [117]

Answer:

The answer to that question is b

Step-by-step explanation:

6 0

2 years ago