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Shtirlitz [24]
3 years ago
12

How can the rate of a reaction be increased?

Physics
2 answers:
VladimirAG [237]3 years ago
7 0

Answer:

<u>A - Increasing the temperature.</u>

<u></u>

Explanation:

<em>Raising the reaction temperature by 10 °C can double or triple the reaction rate. This is due to an increase in the number of particles that have the minimum energy required. The reaction rate decreases with a decrease in temperature.</em>

artcher [175]3 years ago
3 0
I think the answer is A- increasing the temperature.
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Answer:

Part a)

F_n = 306 N

Part b)

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Explanation:

Part a)

By force equation on the rider at the position of the hump we can say

mg - F_n = ma_c

now we will have

mg - F_n = \frac{mv^2}{R}

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now we have

F_n = 100(9.81) - \frac{100(9^2)}{12}

F_n = 981 - 675

F_n = 306 N

Part b)

At the top of the loop if the minimum speed is required so that it remains in contact so we will have

F_n + mg = ma_c

F_n = 0 at minimum speed

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = \sqrt{15 \times 9.81}

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3 years ago
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Answer:

Explanation:I don't say you must have to mark my ans as brainliest but if you think it has really helped u plz don't forget to thank me....

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What is the weight of a 225kg space probe on the moon and the acceleration of gravity on the moon is 1.62
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</span>
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What happens if :<br> . The test charge is not tiny.
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The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

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Adjusting the amount of charge on the test charge will not change the electric field force.

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The charge that is used to measure the electric field strength is directed to as a test charge since it is used to test the field strength. The test charge has a portion of charge denoted by the symbol q.

To learn more about test charge, refer

brainly.com/question/16737526

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