The basic unit of life, it can be seen wit microscopes
Answer:
L = 0 m
Therefore, the cricket was 0m off the ground when it became Moe’s lunch.
Explanation:
Let L represent Moe's height during the leap.
Moe's velocity v at any point in time during the leap is;
v = dL/dt = u - gt .......1
Where;
u = it's initial speed
g = acceleration due to gravity on Mars
t = time
The determine how far the cricket was off the ground when it became Moe’s lunch.
We need to integrate equation 1 with respect to t
L = ∫dL/dt = ∫( u - gt)
L = ut - 0.5gt^2 + L₀
Where;
L₀ = Moe's initial height = 0
u = 105m/s
t = 56 s
g = 3.75 m/s^2
Substituting the values, we have;
L = (105×56) -(0.5×3.75×56^2) + 0
L = 0 m
Therefore, the cricket was 0m off the ground when it became Moe’s lunch.
A rigid outer lair covering for the body in some invertebrate animals, especially arthropods, providing both support and protection. and is made of <span>chitin, a substance produced by many non-arthropods as well.</span>
In radio communication, "frequency modulation" refers to encoding a wave with information by adjusting how many waves are produced per second.<em> (b) </em>That's the "frequency" of the radio carrier signal.
