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max2010maxim [7]

2 years ago

11

A measure of the disoder of a system is called ____

1 answer:

musickatia [10]2 years ago

6 0

Answer: Entropy is basically a thermodynamic quantity that tells the randomness of a system or as said in the question tells us a measure of the disorder of the system. The second law of thermodynamics states that a closed system has entropy which may remain constant

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What is the period of oscillation of a mass 40kg on a spring with constant k=10N/m?

iVinArrow [24]

The period of oscillation of the system is 12.56 s

Explanation:

The period of oscillation of a spring-mass system is given by

$T=2\pi \sqrt{\frac{m}{k}}$

where

m is the mass attached to the spring

k is the spring constant

For the system in this problem, we have

m = 40 kg

k = 10 N/m

Substituting into the equation, we find

$T=2\pi \sqrt{\frac{40}{10}}=12.56 s$

#LearnwithBrainly

7 0

3 years ago

Which objects would be considered to be in free fall?

SVEN [57.7K]

Answer:

Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.

Explanation:

8 0

2 years ago

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N 1800kg car has an<br> of 3.8m/s? What is it<br> on the car?<br> acceleration<br> force acting

nevsk [136]

Answer:

6840 N

Explanation:

The force acting on the car can be found by using Newton's second law:

F = ma

where

F is the net force on the car

m is the mass of the car

a is its acceleration

For the car in this problem,

m = 1800 kg

$a=3.8 m/s^2$

Substituting,

$F=(1800)(3.8)=6840 N$

7 0

2 years ago

In a semiclassical model of the hydrogen atom, the electron orbits the proton at a distance of 0.053 nm. Part A What is the elec

Bezzdna [24]

Answer with Explanation:

We are given that

$r=0.053 nm=0.053\times 10^{-9} m$

$1 nm=10^{-9} m$

Charge on proton,q= $1.6\times 10^{-19} C$

a.We have to find the electric potential of the proton at the position of the electron.

We know that the electric potential

$V=\frac{kq}{r}$

Where $k=9\times 10^9$

$V=\frac{9\times 10^9\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}$

$V=27.17 V$

B.Potential energy of electron,U= $\frac{kq_e q_p}{r}$

Where

$q_e=-1.6\times 10^{-19} c=$ Charge on electron

$q_p=q=1.6\times 10^{-19} C$ =Charge on proton

Using the formula

$U=\frac{9\times 10^9\times (-1.6\times 10^{-19}\times 1.6\times 10^{-19}}{0.053\times 10^{-9}}$

$U=-4.35\times 10^{-18} J$

8 0

3 years ago

A plane flying against a jet stream will travel faster than a plane traveling with a jet stream. Please select the best answer f

stepan [7]

"with the wind" is a tail-wind, and the speeds are added to get the groundspeed.

"against the wind" is a head-wind, and the windspeed is subtracted from the airspeed.

3 0

2 years ago

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