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Law Incorporation [45]
3 years ago
14

Imagine you have been asked to create an experimental design to test the hypothesis that talking on a cell phone impairs driving

skills. Explain why a control condition would be important to include in testing this hypothesis. How should subjects be assigned to conditions? How can the researchers design the experiment so that the only difference between both conditions is the use of a cell phone?
Physics
2 answers:
joja [24]3 years ago
7 0
To start the control would be import to see how drivers would act with full focus on the road. The subjects should (in order for the only difference to be the phone) is to use the same vehicle same road same weather condition, just obviously one has the phone the other does not. I hope this helps
Orlov [11]3 years ago
7 0

Explanation:

To see if using a cell phone actually impairs driving skills, it is necessary to conduct an experiment to test this hypothesis. We can define an experiment as a controlled test to affirm a certain behavior (hypothesis). This is an important procedure to discover the causes and effects that will be important to complete an experiment, so when performing this test it is necessary for a researcher to manipulate a variable in order to find out what its effects are on another variable, so that conclusions about cause and effect.

Every experiment must have an independent variable and a dependent variable. The independent variable is configured as the experimental situation manipulated by the researcher, and the dependent variable is defined as the behavior that the researcher tries to predict. In this question, then, the independent variable is the use of the cell phone, and the dependent variable is the number of collisions.

Therefore, to be valid, an experiment must have an experimental condition and a control condition.

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Define Plateau period.
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A plateau period refers to a period in life where you are kind of stuck in the middle. There is little growth or decline so you are kind of at a standstill.

please vote my answer brainliest. thanks!
5 0
3 years ago
An object is moving east with a constant speed of 30 m/s for 5 seconds. What is the object's acceleration
pentagon [3]

Answer:

<h3>The answer is 6 m/s²</h3>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

where

v is the velocity

t is the time

We have

a =  \frac{30}{5}  \\

We have the final answer as

<h3>6 m/s²</h3>

Hope this helps you

5 0
3 years ago
What is the displacement of the armadillo between 0s and 24s ?
Ann [662]

Answer:

Displacement: 6 meters

Distance: 24 meters

Explanation:

4 0
2 years ago
A tin can has a volume of 1100 cm³ and a mass of 80 g. Approximately how many grams of lead shot can it carry without sinking in
Kruka [31]

Answer:

1020g

Explanation:

Volume of can=1100cm^3=1100\times 10^{-6}m^3

1cm^3=10^{-6}m^3

Mass of can=80g=\frac{80}{1000}=0.08kg

1Kg=1000g

Density of lead=11.4g/cm^3=11.4\times 10^{3}=11400kg/m^3

By using 1g/cm^3=10^3kg/m^3

We have to find the mass of lead which shot can it carry without sinking in water.

Before sinking the can  and lead inside it they are floating in the water.

Buoyancy force =F_b=Weight of can+weight of lead

\rho_wV_cg=m_cg+m_lg

Where \rho_w=10^3kg/m^3=Density of water

m_c=Mass of can

m_l=Mass of lead

V_c=Volume of can

Substitute the values then we get

1000\times 1100\times 10^{-6}=0.08+m_l

1.1-0.08=m_l

m_l=1.02 kg=1.02\times 1000=1020g

1 kg=1000g

Hence, 1020 grams of lead shot can it carry without sinking water.

4 0
3 years ago
please help me guys please please please please please please please please please please please please please​
Maurinko [17]
Someone write the answers???

5 0
3 years ago
Read 2 more answers
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