1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Law Incorporation [45]
3 years ago
14

Imagine you have been asked to create an experimental design to test the hypothesis that talking on a cell phone impairs driving

skills. Explain why a control condition would be important to include in testing this hypothesis. How should subjects be assigned to conditions? How can the researchers design the experiment so that the only difference between both conditions is the use of a cell phone?
Physics
2 answers:
joja [24]3 years ago
7 0
To start the control would be import to see how drivers would act with full focus on the road. The subjects should (in order for the only difference to be the phone) is to use the same vehicle same road same weather condition, just obviously one has the phone the other does not. I hope this helps
Orlov [11]3 years ago
7 0

Explanation:

To see if using a cell phone actually impairs driving skills, it is necessary to conduct an experiment to test this hypothesis. We can define an experiment as a controlled test to affirm a certain behavior (hypothesis). This is an important procedure to discover the causes and effects that will be important to complete an experiment, so when performing this test it is necessary for a researcher to manipulate a variable in order to find out what its effects are on another variable, so that conclusions about cause and effect.

Every experiment must have an independent variable and a dependent variable. The independent variable is configured as the experimental situation manipulated by the researcher, and the dependent variable is defined as the behavior that the researcher tries to predict. In this question, then, the independent variable is the use of the cell phone, and the dependent variable is the number of collisions.

Therefore, to be valid, an experiment must have an experimental condition and a control condition.

You might be interested in
A bowling ball has a mass of 5 kg. A student rolls the bowling ball one time at 1 m/s and a second time and 2 m/s. Compare the m
sasho [114]
The answer is 5kg m/s with the second momentum being 10 kg m/s. i took the test and it was right. hope this helps yalls
5 0
2 years ago
If only 10 pounds is required to lift a 500-lb block, how much chain must be played out to lift the engine 3.0 inches?
adelina 88 [10]

Answer:

150 inches (12.5 ft)

Explanation:

The work done to lift the 500 pound block 3 inches should be the same as that to lift the 10 pond object a given distance.

The following is the equation one needs to solve:

10 \,lb\,* \,x\,=\,500\,lb\,*\,3\,in\\10 \,lb\,* \,x\,=\,1500\,lb\,in\\

therefore solving for the distance "x" gives as the answer (in inches):

10 \,lb\,* \,x\,=\,1500\,lb\,in\\x\,=\,\frac{1500\,lb\,in}{10\,lb} \\\\x\,=150\,in

which can also be given in feet as: 12.5 ft

3 0
3 years ago
Define 1 kg of mass as international standard​
Ann [662]
The kilogram is the Standard International System of Units unit of mass. It is defined as the mass of a particular international prototype made of platinum-iridium and kept at the International Bureau of Weights and Measures.
8 0
3 years ago
Read 2 more answers
Please help!!!
Zolol [24]

Answer:

48

Explanation:

you basically divide 1200 into 25

8 0
3 years ago
if a ball is thrown straight up into the air with an initial velocity of 8080 ft/s, its height in feet after tt second is given
yanalaym [24]

The average velocity for the time period beginning when t=1 and lasting

(i) 0.01 seconds = 63.84 ft/s

(ii) 0.001 seconds = 63.984 ft/s

Given that a ball is thrown with an initial velocity = 80 ft/s

Let 'y' be the height in feet after 't' seconds.

Given,  y=80t-16t^2 gives the height in 't' seconds.

Average velocity = Rate of change of distance

                             = Change in distance/Change in time.

The initial time can be taken as 0 s.

When t =1 s, y = 80 - 16 = 64 ft

(1)  t = 0.01 s

    y = 80 x 0.01 - 16 x 0.01 x 0.01 = 0.7984 ft

    Average velocity = (64 - 0.7984) / (1 -0.01) = 63.84 ft/s

(2) t = 0.001 s

    y = 80 x 0.001 - 16 x 0.001 x 0.001 = 0.079984 ft

    Average velocity = (64 - 0.079984) / (1 -0.001) = 63.984 ft/s

The question is incomplete. Find out the complete question below:

If a ball is thrown straight up into the air with an initial velocity of 80 ft/s, it height in feet after t second is given by  y=80t-16t^2 .Find the average velocity for the time period beginning when t=1 and lasting

(i) 0.01 seconds

(ii) 0.001 seconds

Learn more about average velocity at brainly.com/question/6504879

#SPJ4

7 0
2 years ago
Other questions:
  • A point charge is at the origin. With this point charge as the source point, what is the unit vector r^ in the direction of (a)
    13·1 answer
  • Two laptop computers each have a mass of 2 kg. If they are 0.5 m apart on a desk, what is the gravitational force between them?
    13·1 answer
  • A mechanic pushes a 3.60 ✕ 103-kg car from rest to a speed of v, doing 5,130 j of work in the process. during this time, the c
    9·1 answer
  • The study of the stars and planets
    13·1 answer
  • Astronauts often undergo special training in which they are subjected to extremely high centripetal accelerations. One device ha
    15·2 answers
  • QUICK HELP PLEASE!
    13·1 answer
  • A trombone acts as if it were an
    6·1 answer
  • Where do you weight more on top of Mt. Everest (Highest Mt. in the world) or at the beach
    12·1 answer
  • Reasons why inductors opposes charges passing through it<br>​
    15·1 answer
  • A 2.00 kg rock is dropped from the top of a 30.0 m high building. Calculate the ball’s momentum at the time that it strikes the
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!