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Law Incorporation [45]
3 years ago
14

Imagine you have been asked to create an experimental design to test the hypothesis that talking on a cell phone impairs driving

skills. Explain why a control condition would be important to include in testing this hypothesis. How should subjects be assigned to conditions? How can the researchers design the experiment so that the only difference between both conditions is the use of a cell phone?
Physics
2 answers:
joja [24]3 years ago
7 0
To start the control would be import to see how drivers would act with full focus on the road. The subjects should (in order for the only difference to be the phone) is to use the same vehicle same road same weather condition, just obviously one has the phone the other does not. I hope this helps
Orlov [11]3 years ago
7 0

Explanation:

To see if using a cell phone actually impairs driving skills, it is necessary to conduct an experiment to test this hypothesis. We can define an experiment as a controlled test to affirm a certain behavior (hypothesis). This is an important procedure to discover the causes and effects that will be important to complete an experiment, so when performing this test it is necessary for a researcher to manipulate a variable in order to find out what its effects are on another variable, so that conclusions about cause and effect.

Every experiment must have an independent variable and a dependent variable. The independent variable is configured as the experimental situation manipulated by the researcher, and the dependent variable is defined as the behavior that the researcher tries to predict. In this question, then, the independent variable is the use of the cell phone, and the dependent variable is the number of collisions.

Therefore, to be valid, an experiment must have an experimental condition and a control condition.

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At divergent boundaries, hot mantle rock rises and<br> occurs.
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A child attempts to roll a ball up a long ramp and it slows as it goes up. If it is released at 2.5 m/s upward and accelerates d
valina [46]

Answer:

-0.7 m/s

Explanation:

Initial velocity (u)= 2.5 m/s

Acceleleration (a)= -0.8 m/s^2

Time taken (t) = 4  seconds

Hence,

v=u+at [1st Equation of motion]

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3 years ago
Which describe the image formed by an object on the center of curvature? Check all that apply.
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The image formed by a concave  mirror with the object placed at the center of curvature is real inverted and formed at the center of curvature. Using the ray diagram a ray from the top of the object to the mirror through f then reflected parallel to the principal axis,then the ray through the center of curvature reflected through the same point both intersect at a plane through center curvature and perpendicular  to the principal axis. The point of intersection forms the top of the image and the center of curvature forms the bottom. Therefore, the correct choices are : real and inverted

5 0
4 years ago
Read 2 more answers
Please help me!
sergeinik [125]

C. The Densities are equal.

<h3>What is density?</h3>

Density is mass per unit volume or mass of a unit volume of a material substance.

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

V_{1} = 3V_{2}  , m_{2}  = \frac{1}{3} (m_{1} ) \\ \\= m_{1} = 3m_{2}

Therefore,

\frac{D_{1} }{D_{2} }  = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{3m_{2} }{3V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 1

Hence, D1 = D2

Learn more about density here:brainly.com/question/15164682

#SPJ1

6 0
3 years ago
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