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3 years ago

How would a small bar magnet be oriented when placed at position X

Physics

2 answers:

kotykmax [81]3 years ago

6 0

Answer:

Explanation:

Well opposites attract, don't they?

Alex Ar [27]3 years ago

4 0

The answer is right here

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A particle with a charge of −1.24×10−8c is moving with instantaneous velocity v⃗ = (4.19×104m/s)i^ + (−3.85×104m/s)j^ . part a w

Bezzdna [24]

Answer:

F = 0i (in the x-direction), 0j (in the y-direction),-8.59*10^-4 N k (In the z-direction)

Explanation:

The force given by charged particles moving in a magnetic field is given below (cross is cross product, they don't have that format in the equation tool):

$F=qv (cross) B\\$

Now we can perform the cross product between v and B

$v(cross)B = \left[\begin{array}{cc}4.19*10^{4} &-3.85*10^{4}\\1.8&0&\en[tex]v(cross)B = 69300 (kg*m/(s^2*C))\\$ d{array}\right][/tex]

Now multiply by Q (charge) to get the force

$F = -1.24*10^-8 * 69300\\F = -8.59*10^-4N$

F = -8.59*10^-4 N k

F = 0i, 0j, (-8.59*10^-4)k

6 0

3 years ago

Read 2 more answers

Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m

Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

distance d = 2 m

we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

Potential difference ΔV = 20287.14 V

Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

E = 10143.57 V/m or 1.01 × 10⁴ V/m

Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

3 0

3 years ago

Which of these follows from Newton's laws about the energy of a moving object?

Rina8888 [55]

<span>Assuming that this is referring to the same list of options that was posted before with this question, the best response is the one having to do with intertia. </span>

6 0

4 years ago

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 81.7 cm and diameter 2.70 cm fr

Genrish500 [490]

Answer:

35.792 N

Explanation:

d = Diameter of rod = 2.7 cm

h = Length of rod = 81.7 cm

$\rho$ = Density of rod = 7800 kg/m³