To solve this task we have to make a proportion, but firstly we have to set up all the main points : so, the distance is s=r(B), that has its <span>r=radius,B=angle in rad
velocity v=ds/dt= w(r)
Do not forget about </span> w = angular speed in rad/s and
Now we can go to proportion
SOLVING FOR A :
or something about <span>10 mph --- SOLVING FOR B.
</span>I'm sure it helps!
Car X traveled 3d distance in t time. Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t, the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.
In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.
Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.
We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.
Answer:
The sun touches earth during daytime and the suns rays heat our earth giving us heat. The sun heating the earth is also considered radiation.
Explanation:
Hey there!
<span>
An object's velocity can be described by its speed and acceleration.
This statement is true
Hope this helps
Have a great day (:
</span>
