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3 years ago

Screws and wedges are modified...

1 answer:

7 0

The correct answer that would best complete the given statement above would be INCLINED PLANES. Screws and wedges are modified inclined planes. An inclined plane that moves is called a wedge and a screw is the result when you take an inclined plane and wrap it around a cylinder. Hope this answer helps you.

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What is the pair of vectors if summed , would create of equilibrium (a resultant of 0i + 0j) ?

bogdanovich [222]

ANY pair of vectors can produce that resultant, as long as ...

If one of the vectors is V₁ = A i + B j . . . . . . where 'A' and 'B' are any two numbers,

then the other one is V₂ = -A i - B j

6 0

4 years ago

Read 2 more answers

When solar flares increase solar wind from the corona what do they cause in earth's upper atmosphere?

Strike441 [17]

They cause magnetic storms. A magnetic storm is a fleeting disturbance of the Earth's magnetosphere. A magnetic storm is caused by a solar wind shock wave associated with solar coronal mass ejections, coronal holes, or solar flares. It typically strikes the Earth's magnetic field 24 to 36 hours after the event.

5 0

4 years ago

A projectile was launched horizontally with a velocity of 388 m/s, 2.89 m above the ground. How long did it take the projectile

tamaranim1 [39]

Answer:

Explanation:

Given

Velocity = 388m/s

Height S = 2.89m

Required

Time

Using the equation of motion

S =ut+1/2gt²

2.89 = 388t+1/2(9.8)t²

2.89 = 388t+4.9t²

Rearrange

4.9t²+388t-2.89 =0

Factorize

t = -388±√388²-4(4.9)(2.89)/2(4.9)

t= -388±√(388²-56.644)/9.8

t = -388±387.93/9.8

t =0.073/9.8

t = 0.00744 seconds

6 0

3 years ago

What frequency (in Hz) is received by a person watching an oncoming ambulance moving at 116 km/h and emitting a steady 950 Hz so

Arte-miy333 [17]

To solve this problem we will apply the concepts related to the Doppler Effect, defined as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically it can be written as

$f_{obs} = f(\frac{v_w}{v_w-v_s})$

Here,

$f_s$ = Frequency of the source

$v_w$ = Speed of the sound

$v_s$ = Speed of source

Now the velocity we have that

$v_s = 116km/h (\frac{1000m}{1km})(\frac{1h}{3600s})$

$v_s = 32.22m/s$

Then replacing our values,

$f_{obs} = (950Hz) (\frac{345m/s}{345m/s-32.22m/s})$

$f_{obs} = 1047.86Hz$

Therefore the frequency of the observer is 1047.86Hz

8 0

3 years ago

A 140-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope a

RUDIKE [14]

Answer:

The constant force is 263.55 newtons

Explanation:

There's a rotational version of the Newton's second law that relates the net torque on an object with its angular acceleration by the equation:

$\tau = I\alpha$ (1)

with τ the net torque and α the angular acceleration. It’s interesting to note the similarity of that equation with the well-known equation F=ma. I that is the moment of inertia is like m in the linear case. The magnitude of a torque is defined as

$\tau = Fr\sin \theta$

with F the force applied in some point, r the distance of the point respect the axis rotation and θ the angle between the force and the radial vector that points toward the point the force is applied, in our case θ=90 and sinθ=1, then (1):

$Fr = I\alpha$ (2)

Because the applied force is constant the angular acceleration is constant too, and for constant angular acceleration we have that it's equal to the change of angular velocity over a period of time:

$\alpha=\frac{0.800}{2.00}=0.40 \frac{rev}{s^{2}}$