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3 years ago

If a star is hotter is the wavelength shorter and higher energy?

Physics

2 answers:

insens350 [35]3 years ago

3 0

Answer:

That is true, the hotter a star is the shorter of wavelength it emits and the higher. It also depends on the mass of the star because the bigger it is, the faster it fuses its hydrogen fuel. Faster burning of fuel means more energy is released and so results in higher temperatures.

Hope this helps! Good luck :)

Explanation:

sveticcg [70]3 years ago

3 0

The energy of the light from the star is dependent on the temperature of the star. The higher the temperature the higher the energy. As the energy of light increases, the wavelength shortens as there is an inverse proportion between the two.

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(35 points!!) A block and tackle is used to lift a load weighing 600 lb. The operator lifts the load distance of 1.25 ft by pull

Drupady [299]

Answer:

A. Input work = 800 ft.lb

B. Output work = 750 ft.lb

C. Efficiency of block and tackle = 93.75 %

Explanation:

Given:

Weight of the load, $W=600$ lb.

Distance moved by the load, $D_{load}=1.25$ ft.

Force applied on the rope, $F = 200$ lb

Distance moved by the force on the rope, $D{in}=4$ ft.

Work done by a force causing a displacement in the direction of force is given as:

$\textrm{Work}=\textrm{Force}\times \textrm{Displacement}$

Here, Input Work is given by the input force and the displacement caused by the input force. So,

$W_{in}=F\times D_{in}\\W_{in}=200\times 4=800\textrm{ ft.lb}$

Therefore, the input work is 800 lb.ft

Output Work is given by the output force and the displacement caused by the output force. So,

$W_{out}=F_{load}\times D_{load}\\W_{out}=600\times 1.25=750\textrm{ ft.lb}$

Therefore, the output work is 750 ft.lb

Efficiency is given as the ratio of Output Work to Input Work expressed as percentage. So,

Efficiency = $\frac{W_{out}}{W_{in}}\times 100=\frac{750}{800}\times 100=93.75\%$

Therefore, efficiency of block and tackle is 93.75 %.

6 0

3 years ago

Read 2 more answers

Help asap!! The resultant force on the box is

rodikova [14]

The resultant force on the box is C) 10 Newtons to the left.

Explanation:

The figure of the problem is attached.

We see that there are two forces acting on the box along the horizontal direction:

- A force of 10 N acting to the right

- A force of 20 N acting to the left

By taking "to the right" as positive direction, we can rewrite the two forces as follows:

$F_1 = +10 N\\F_2 = -20 N$

Where the second force is negative since it acts to the left.

Since the two forces are in line, we can find their resultant simply by calculating their algebraic sum. By doing so, we find:

$F=F_1 + F_2 = +10 + (-20) = -10 N$

And the negative sign tells us that the direction is to the left.

Therefore, the correct answer is

C) 10 Newtons to the left.

Learn more about forces here:

brainly.com/question/12978926

#LearnwithBrainly

5 0

3 years ago

Even through there is equal and opposite reaction,usually the two forces are not seen balanced.Why?

Tomtit [17]

Answer:

This may refer to a situation like:

"one person pushes a box, if there is equal and opposite reaction why the box moves and the person does not?"

Remember the second Newton's law:

F = m*a

suppose that the mass of the person is 3 times the mass of the box.

So, if the box has a mass M, the person will have a mass 3*M

Then the Newton's equation for the box when the person pushes with a force F is:

F = M*a

solving for the acceleration, we get:

F/M = a

While the person is also pushed by the box with a force with the same magnitude, then the equation for the person is:

F = (3*M)*a'

Solving for the acceleration, we get:

F/(3M) = a'

Now we can compare the acceleration of the box (F/M) with the acceleration of the person (F/3M).

Is easy to see that the acceleration of the box is 3 times the acceleration of the person.

So regardless of the fact that both the box and the person experience a force with the same magnitude, the box will move more due to this force.

This is why in situations like this, the forces do not seem balanced.

5 0

3 years ago

Suppose a star has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 ) but is located at a distance of 300 ligh

iragen [17]

For a star that has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 is mathematically given as

L=2.7*10^30w

<h3> What is its luminosity?</h3>

Generally, the equation for the luminosity is mathematically given as

L=4*\pi^2*b

Therefore

L=4*\pi^2*b

L=4* \pi *(2.83*10^{18})*2.7*10^{-8}

L=2.7*10^30

In conclusion, the luminosity

L=2.7*10^30w