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VikaD [51]
3 years ago
14

A wagon full of manure accidentally rolls down a driveway for 5.0m while a person pushes against the wagon with a force of 420 N

to bring it to a stop. What is the change in kinetic energy for the wagon?
Physics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

2100 J

Explanation:

Parameters given:

Force acting on the object, F = 420 N

Distance moved by object, d = 5m

The change in kinetic energy of an object is equal to the work done by a force acting on the object:

W = F * d

∆KE = F * d

∆KE = 420 * 5

∆KE = 2100 J

Studentka2010 [4]3 years ago
6 0

Answer:

∆KE = 2100 J

Explanation:

Given:

Force of person pushes against the wagon=  F = 420 N

Distance = d = 5.0 m

When you accelerate an object, you are doing work against inertia. It is proven that work equals the change in kinetic energy of the object.

therefore, W = ΔKE

where,

W is the work done against the resistance of inertia

ΔKE is the change in kinetic energy (Δ is Greek letter capital delta)

Also, W = F x d

∴∆KE = F x d

∆KE = 420 x 5

∆KE = 2100 J

The change in kinetic energy for the wagon is 2100 J

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Answer:

work done lifting the bucket (sand and rope) to the top of the building,

W=67.46 Nm

Explanation:

in this question we have given

mass of bucket=20kg

mass of rope=.2\frac{kg}{m}

height of building= 15 meter

We have to find the work done lifting the bucket (sand and rope) to the building =work done in lifting the rope + work done in lifting the sand

work done in lifting the rope is given as,W_{1}=Force \times displacement

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=.1\times 15^2

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work done in lifting the sand is given as,W_{2}=Force \times displacement

W_{2}=\int\limits^{15}_0 F \, dx.................(2)

Here,

F=mx+c

here,

c=20-18

c=2

m=\frac{20-18}{15-0}

m=.133

Therefore,

F=.133x+2

Put value of F in equation 2

W_{2}=\int\limits^{15}_0 (.133x+2) \, dx

W_{2}=.133 \times 112.5+2\times15\\W_{2}=14.96+30\\W_{2}=44.96 Nm

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,W=W_{1}+W_{2}

W=22.5 Nm+44.96 Nm

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4 0
3 years ago
I need a short answer ?
mars1129 [50]

Answer:

Explanation:

7a) t = d/v = 100/45cos14.5 = 2.29533...= 2.30 s

7b) h = ½(9.81)(2.29533/2)² = 6.46056... = 6.45 m

  or

  h = (45sin14.5)² / (2(9.81)) = 6.47 m

which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.

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an object at rest starts accelerating if it travels 30 meters to end up going 10 m/s what was it’s acceleration
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First we have to calculate the time taken to travel the distance 30 m, is

t = \frac{distance}{velocity} = \frac{30 \ m}{10 \ m/s } =  3 \ s.

Now from equation of motion,

v = u + at

Given, v = 10 \ m/s .

As object starts from rest, so  u = 0.

Substituting these values in above equation, we get

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Thus, the acceleration is 3.33 \ m/s^2

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an op amp in unity gain configuration (buffer) with slew rate of 5v/us is used to amplify a sinusoidal signal with a frequency o
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Answer:

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