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VikaD [51]
3 years ago
14

A wagon full of manure accidentally rolls down a driveway for 5.0m while a person pushes against the wagon with a force of 420 N

to bring it to a stop. What is the change in kinetic energy for the wagon?
Physics
2 answers:
Cerrena [4.2K]3 years ago
8 0

Answer:

2100 J

Explanation:

Parameters given:

Force acting on the object, F = 420 N

Distance moved by object, d = 5m

The change in kinetic energy of an object is equal to the work done by a force acting on the object:

W = F * d

∆KE = F * d

∆KE = 420 * 5

∆KE = 2100 J

Studentka2010 [4]3 years ago
6 0

Answer:

∆KE = 2100 J

Explanation:

Given:

Force of person pushes against the wagon=  F = 420 N

Distance = d = 5.0 m

When you accelerate an object, you are doing work against inertia. It is proven that work equals the change in kinetic energy of the object.

therefore, W = ΔKE

where,

W is the work done against the resistance of inertia

ΔKE is the change in kinetic energy (Δ is Greek letter capital delta)

Also, W = F x d

∴∆KE = F x d

∆KE = 420 x 5

∆KE = 2100 J

The change in kinetic energy for the wagon is 2100 J

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11430\times ( 1.29 - \rho_{hot \ air } ) = 1890\\\\\rho_{hot \ air } = 1.29 - \dfrac{1890}{11430}\\\\\rho_{hot \ air } =  1.125\ kg\ m^3

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4 0
3 years ago
A 5.0 kg box slides down a 4.0 m long ramp that makes a 25 angle with the ground. If the coefficient of kinetic friction is 0.65
Sedaia [141]

The thermal energy was produced is 116J

<h3>What is the thermal energy produced?</h3>

Now we know that the frictional force produces the energy that is lost as heat as the body slides down the incline. The magnitude of the frictional force is obtained from;

Ff= μmgcosθ

Ff =  0.65 *  5.0 kg * 9.8 m/s^2 * cos 25

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4 0
2 years ago
Dan is gliding on his skateboard at 2.00 m/s . He suddenly jumps backward off the skateboard, kicking the skateboard forward at
miss Akunina [59]

Answer:

The velocity of Dan is 1.13 m/s.

Explanation:

Given that,

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Using conservation of momentum

(m+M)v_{i}=mv_{f}+Mv_{f}

Put the value into the formula

(40.0+7.00)\times2.00=40.0\times v_{i}+7.00\times7.00

v_{i}=\dfrac{(40.0+7.00)\times2.00-7.00\times7.00}{40.0}

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4 0
3 years ago
A ball is dropped from a cliff that is 464 feet high. The height of the ball (in feet) after t seconds is given by the formula h
Sedbober [7]

Answer:

At 5.38 seconds the ball hits the ground.

Explanation:

It is given that,

The height of the ball after t seconds is given by the formula as :

h(t)=464-16t^2

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When the ball hits the ground, its height is equal to 0. So,

464-16t^2=0

On solving the above equation we get:

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So, at 5.38 seconds the ball hits the ground. Hence, this is the required solution.

8 0
3 years ago
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o-na [289]

Answer:

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The vertical component of velocity is the same for both since the only force acting on y is the gravity. And we can assume that the horizontal component is constant without acceleration.

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v = \sqrt{v^2_x +v^2_y}

a) the speed of Alice is larger than that of Tom

Explanation:

For this case we can use the following kinematic equation:

v_f = v_i + a t

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So then the best option for this case is:

a) the speed of Alice is larger than that of Tom

4 0
4 years ago
Read 2 more answers
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