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inysia [295]
3 years ago
8

Which technology is used to service space vehicles and other equipment?

Physics
1 answer:
Crank3 years ago
6 0
You’re correct hope this helps :)
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During an ,
nadya68 [22]

Answer:

1.5*10^9

Explanation:

distance =V x T

=3x10^8x5

=1.5*10^9

8 0
3 years ago
Magnets are created due to the uniform motion of
Alinara [238K]
<span>Magnets are created due to the uniform motion of "Electrons"

Hope this helps!</span>
7 0
3 years ago
Read 2 more answers
A cricketer moves his hands backwards when holding a catch
lisov135 [29]
By doing this he increases the time due to which the rate of change momnetemdecreases. that means the ball comes to rest gently and does not hurt the fielder. but, if does not move his hand backwards, then the ball would come to rest in a fraction of second with a high rate of change of momentum. the ball will exert a lot of force on the hands of the fielder which will hurt him.
3 0
3 years ago
A sound wave has a speed of 340 m/s and a frequency of 1000 hz. The period of the sound is closest to?
harina [27]
<h2>Relationship Between Frequency and Period</h2>

The frequency and the period are inversely proportional.

f=\dfrac{1}{T} where T is the period

<h2>Solving the Question</h2>

We're given:

  • <em>v</em> = 340 m/s
  • <em>f</em> = 1000 Hz

Because the frequency and the period are reciprocals of each other, we can find the period of the sound by finding the reciprocal of the frequency:

T=\dfrac{1}{1000}

<h2>Answer</h2>

T=\dfrac{1}{1000}

6 0
2 years ago
The constellation Canis Minor has a binary star system consisting of Procyon A and Procyon B. Procyon A, at 3×1030kg, has 2.5 ti
denis-greek [22]

This question involves the concepts of Newton's Law of Gravitation and mass.

The force on Procyon A from Procyon B will be "equal" to the force on Procyon B from Procyon A, which has a value of "3.75 x 10²⁶ N".

Applying Newton's Law of Gravitation, we can find the force on Procyon A from Procyon B, which is equal to the force on Procyon B from Procyon A:

F=\frac{Gm_1m_2}{r^2}

where,

F = force = ?

G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = mass of Procyon A = 3 x 10³⁰ kg

m₂ = mass of Procyon B = (2.5)(3 x 10³⁰ kg) = 7.5 x 10³⁰ kg

r = distance between them = 2 x 10¹² m

Therefore,

F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(3\ x\ 10^{30}\ kg)(7.5\ x\ 10^{30}\ kg)}{(2\ x\ 10^{12}\ m)^2}

<u>F = 3.75 x 10²⁶ N</u>

Learn more about Newton's Law of Gravitation here:

brainly.com/question/17931361?referrer=searchResults

6 0
3 years ago
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