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Trava [24]
2 years ago
5

I need help, Will mark branliest!

Physics
2 answers:
inna [77]2 years ago
3 0
I believe you are correct with C.
Scorpion4ik [409]2 years ago
3 0

Answer:

i know what it is it is A i say that because i have been learning about this stuff latley

Explanation:

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Besides the force due to gravity or g, what else determines the period of a pendulum?
Hoochie [10]
For a simple pendulum, the mathematical equation that describes the period (T) is T=√(l/g) where l is the length of the string and g is the acceleration due to gravity (9.81 metres per second). Therefore it can be seen that both gravity and the length of the string within a pendulum effects its period. 
5 0
3 years ago
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Equivalent resistance between A and B.<br>A) 2.4 ohms<br>B)18 ohms<br>C) 6 ohms<br>D) 36 ohms ​
IgorLugansk [536]
<h3><u>Answer</u> :</h3>

First of all see the attachment for better understanding. :D

<u>Eq. resistance between C and D</u> :

➝ 1/Rp = 1/6 + 1/6

➝ 1/Rp = 2/6

➝ <u>Rp = 3Ω</u>

<u>E</u><u>q. resistance of upper part </u>:

(All three are in series)

➝ Rs = 3 + 3 + 3

➝ <u>Rs = </u><u>9</u><u>Ω</u>

<u>Eq. resistance of lower part</u> :

(Both are in series)

➝ Rs' = 3 + 3

➝ <u>Rs' = 6Ω</u>

<u>Eq. resistance between A and B </u>:

(Rs and Rs' are in parallel)

➝ 1/Req = 1/Rs + 1/Rs'

➝ 1/Req = 1/9 + 1/6

➝ 1/Req = (2 + 3)/18

➝ Req = 18/5

<h3>➝ <u>Req = </u><u>3</u><u>.</u><u>6</u><u>Ω</u></h3>

7 0
3 years ago
Read 2 more answers
A 40,000 kg subway train is brought to a stop from a speed of 0.700 m/s in 0.250 m by a large spring bumper at the end of its tr
lozanna [386]

Given,

The mass of the train, m=40000 kg

The initial velocity of the train, u=0.700 m/s

The compression in the spring bumper that stopped the train, x=0.250 m

The final velocity of the train, v=0 m/s

From the equation of motion,

v^2-u^2=2ax

Where a is the acceleration of the train.

On substituting the known values,

\begin{gathered} 0-0.700^2=2a\times0.250 \\ \Rightarrow a=\frac{-0.700^2}{2\times0.25} \\ =-0.98\text{ m/s}^2 \end{gathered}

The magnitude of the force applied by the train will be equal to the magnitude of the restoring force of the spring.

Therefore,

\begin{gathered} m|a|=kx \\ \Rightarrow k=\frac{m|a|}{x} \end{gathered}

Where k is the spring constant of the spring.

On substituting the known values,

\begin{gathered} k=\frac{40000\times0.98}{0.250} \\ =156800\text{ N/m} \end{gathered}

Therefore the spring constant of the spring is 156800 N/m

Thus the correct answer is option C.

5 0
1 year ago
An object with a mass of 10 kg is
shusha [124]

Answer:

See below

Explanation:

They will fall at the same speed .....they will stay together if we ignore air friction

8 0
2 years ago
An MRI technician moves his hand from a region of very low magnetic field strength into an MRI scanner's 2.00 T field with his f
makkiz [27]

Answer:

2.62 A

Explanation:

B = 2 T, Diameter = 2.5 cm , radius, r = 0.0125 m, t = 0.45 s, r = 0.01 ohm

Induced emf, e = rate of change of magnetic flux

e = A x dB / dt = 3.14 x (0.0125)^2 x 2 / 0.45

e = 0.026 V

induced current, i = e / R = 0.026 / 0.01 = 2.62 A

7 0
2 years ago
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