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3 years ago

I need help, Will mark branliest!

Physics

2 answers:

inna [77]3 years ago

3 0

I believe you are correct with C.

Scorpion4ik [409]3 years ago

3 0

Answer:

i know what it is it is A i say that because i have been learning about this stuff latley

Explanation:

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The constant forces F1 = 8 + 29 + 32 N and F2 = 48 - 59 - 22 N act together on a particle during a displacement from the point A

marshall27 [118]

Answer:

-600 J

Explanation:

F₁ = 8i +29 j + 32k

F₂ = 48 i - 59 j - 22 k

F = F₁ +F₂ = 8i +29 j + 32k +48 i - 59 j - 22 k

F = 56i - 30 j + 10 k

displacement d = ( 0 - 20 )i + ( 0 - 15 )j + ( 7 -0) k

d = - 20 i - 15 j + 7 k

Work Done = F dot product d

F . d = - 56 x 20 - 30 x - 15 + 10 x 7

= - 1120 +450 + 70

= -600 J

5 0

3 years ago

Young's Modulus of elasticity is a) Shear stress/Shear strain b) Tensile stress/Shear strain 9. c) Shear stress /Tensile strairn

slava [35]

Answer:

Option C is the correct answer.

Explanation:

Young's modulus is the ratio of tensile stress and tensile strain.

Bulk modulus is the ratio of pressure and volume strain.

Rigidity modulus is the ratio of shear stress and shear strain.

Here we are asked about Young's modulus which is the ratio of tensile stress and tensile strain.

Option C is the correct answer.

3 0

3 years ago

Read 2 more answers

Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that th

lozanna [386]

Answer:

Part a)

Velocity of sled

$v = \frac{m_1 s}{m_1 + m_2 + M}$

velocity of first man who jump off

$v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}$

Part b)

Velocity of sled

$v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s$

Also the speed of second person is given as

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}$

Part c)

change in kinetic energy of sled + two people is given as

$KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

Explanation:

As we know that here we we consider both people + sled as a system then there is no external force on it

So here we can use momentum conservation

since both people + sled is at rest initially so initial total momentum is zero

now when first people will jump with relative velocity "s" then let say the sled + other people will move off with speed v

so by momentum conservation we have

$0 = m_1(v - s) + (m_2 + M)v$

$v = \frac{m_1 s}{m_1 + m_2 + M}$

so velocity of the sled + other person is

$v = \frac{m_1 s}{m_1 + m_2 + M}$

velocity of first man who jump off

$v_1 = \frac{m_1 s}{m_1 + m_2 + M} - s$

$v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}$

Part b)

now when other man also jump off with same relative velocity

so let say the sled is now moving with speed vf

so by momentum conservation we have

$(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) = m_2(v_f - s) + Mv_f$

$(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) + m_2s = (m_2 + M)v_f$

Now we have

$v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s$

Also the speed of second person is given as

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s - s$

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}$

Part c)

change in kinetic energy of sled + two people is given as

$KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

here we know all values of speed as we found it in part a) and part b)

4 0

3 years ago

Your laundry basket Please 22 is in your room is 3.0 M above you on the second floor it takes you 6.0 seconds to carry the laund

Rainbow [258]

Power = (work done) / (time to do the work)

Work done = (force to lift the object) x (distance lifted)

In this question, the force is the (weight of the basket)+(your weight).

Work done = (weight of basket+you) x (3 meters)

Time to do the work = 6 seconds.

Power = (weights x 3 meters) / (6 seconds)

<em>Power = (1/2)·(weight of the basket+you, in Newtons) watts</em>

8 0

3 years ago

Read 2 more answers

Light of wavelength 480 nm illuminates a pair of slits separated by 0.27 mm. If a screen is place 1.7 m from the slits, determin

Dahasolnce [82]

Answer:

Δy = 6.05 mm

Explanation:

The double slit phenomenon is described by the expression

d sin θ = m λ constructive interference

d sin θ = (m + ½) λ destructive interference

m = 0,±1, ±2, ...

As they tell us that they measure the dark stripes, we are in a case of destructive interference, let's use trigonometry to find the sins tea

tan θ = y / x

y = x tan θ

In the interference experiments the measured angle is very small so we can approximate the tangent

tan θ = sin θ / cos θ

cos θ = 1

tan θ = sin θ

y = x sin θ

We substitute in the destructive interference equation

d (y / x) = (m + ½) λ

y = (m + ½) λ x / d

The first dark strip occurs for m = 0 and the third dark strip for m = 2. Let's find the distance for these and subtract it

m = 0

y₀ = (0+ ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

y₀ = 1.511 10⁻³ m

m = 2

y₂ = (2 + ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

y₂ = 7.556 10⁻³ m

The separation between these strips is Δy

Δy = y₂-y₀

Δy = (7.556 - 1.511) 10⁻³

Δy = 6.045 10⁻³ m

Δy = 6.05 mm

5 0

3 years ago