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egoroff_w [7]
3 years ago
14

A 35.1 kg wagon is towed up a hill inclined at 18.3 ◦ with respect to the horizontal. The tow rope is parallel to the incline an

d has a tension of 125 N in it. Assume that the wagon starts from rest at the bottom of the hill, and neglect friction. The acceleration of gravity is 9.8 m/s 2 . How fast is the wagon going after moving 75.4 m up the hill? Answer in units of m/s.
Physics
1 answer:
allsm [11]3 years ago
3 0

Answer:

4.933m/s

Explanation:

the wagon has a weight of <u>35.1kg*9.81m/s2 = 343.98N</u>

of that weight <u>343.98N*sin(18.3)=108N </u>are parallel to the hill and oposit tothe tension of the rope.

then, the force that is moving the wagon is <u>125N-108N=17N</u>

<u>F=m*a then 17N=35.1kg*a</u>

<u>a=0.4843 m/s2</u>

we have two equations

v=a.t\\x=v.t+\frac{1}{2} . a . t^{2}

then

x=a.t^{2} +\frac{1}{2}. a t^{2} \\x=\frac{3}{2}. a t^{2}

t=\sqrt{\frac{2x}{3a} }

t=10.188s

v=a.t

<em><u>v=4.933 m/s</u></em>

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