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3 years ago

Why are we mentley unstable to time travle

Physics

1 answer:

leva [86]3 years ago

8 0

Answer:

Mental time travel has been studied by psychologists, cognitive neuroscientists, philosophers and in a variety of other academic disciplines. Major areas of interest include the nature of the relationship between memory and foresight, the evolution of the ability (including whether it is uniquely human or shared with other animals), its development in young children, its underlying brain mechanisms, as well as its potential links to consciousness, the self, and free will.

Explanation:

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Acceleration is defined as the change in velocity divided by

mihalych1998 [28]

Answer:

change in time

Explanation:

8 0

3 years ago

3. No simple machine is ideal in practice.<br>Why

Kobotan [32]

Answer:

beacuase

Explanation:

4 0

3 years ago

The specific heat capacity of ethanol is 2440J/kg °C. How many joules of energy will be required to heat 150g ethanol to 35°C if

m_a_m_a [10]

Answer:

Required energy = 4758 J

Explanation:

Specific heat capacity of a material is the amount of energy required to raise the temperature of one kilogram (kg) of that material through one degree Celsius (°C).

Given data :

Specific heat capacity = c = 2440 J/kg.°C

Mass = m = 150 g = 0.15 kg

Initial temperature = 22°C

Final temperature = 35°C

Change in Temperature = ΔT = 13°C

Energy = E = ?

Using the following formula and substituting the values, we get:

E = m × c × ΔT

E = 0.15 × 2440 × 13

E = 4758 J

8 0

3 years ago

In which direction would the circle go if it was in between a positive and negative charge

evablogger [386]

It would go to the positive charge im like 99% sure of that

7 0

3 years ago

As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr

Natalija [7]

Answer:

a) F = 680 N, b) W = 215 .4 J , c) F = 1278.4 N

Explanation:

a) Hooke's law is

F = k x

To find the displacement (x) let's use the elastic energy equation

$K_{e}$ = ½ k x²

k = 2 $K_{e}$ / x²

k = 2 85.0 / 0.250²

k = 2720 N / m

We replace and look for elastic force

F = 2720 0.250

F = 680 N

b) The definition of work is

W = ΔEm

W = $K_{ef}$ - $K_{eo}$

W = ½ k ( $x_{f}$ ² - x₀²)

The final distance

$x_{f}$ = 0.250 +0.220

$x_{f}$ = 0.4750 m

We calculate the work

W = ½ 2720 (0.47² - 0.25²)

W = 215 .4 J

We calculate the strength

F = k $x_{f}$

F = 2720 0.470

F = 1278.4 N

6 0

3 years ago