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Viefleur [7K]
3 years ago
5

I honestly don't even know where to start //// on his last 4 tests , Danilo scored 55% 78% 84% and 93%. What score should he get

on the next test so that his average on all five tests is 80%?
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

The answer to your question is He must get 80%

Step-by-step explanation:

Data

Scores 55%, 78%, 84%, 93% and X

Average 80%

Process

1.- Write a equation to solve this problem

- There are five scores

Score 1 = S1 = 55

Score 2 = S2 =  78

Score 3 = S3 = 84

Score 4 = S4 = 93

Score 5 = S5 = X

Equation

               Average = (S1 + S2 + S3 + S4 + S5) / 5

- Solve for S5

               5 Average = S1 + S2 + S3 + S4 + S5

               S5 = 5 Average - S1 - S2 - S3 - S4

- Substitution

               S5 = 5(80) - 55 - 78 - 84 - 93

- Simplification

               S5 = 400 - 310

- Result

               S5 = 90

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When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100
ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the <em>future value FV.</em>  

In order to see the rule of formation, let's see the value (in $) for the first few years

<u>End of year 0</u>

1,000

<u>End of year 1(capital + interest + new deposit)</u>

1,000*(1.09)+10  

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

\bf 1,000*(1.09)^2+10(1+1.09)

<u>End of year 3 (capital + interest + new deposit)</u>

\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)

and we can see that at the end of year 50, the future value is

\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}

The sum  

\bf 1+1.09+(1.09)^2+...+(1.09)^{49}

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356

and the future value is then

\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564

The <em>present value PV</em> is

\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62

rounded to the nearest hundredth.

5 0
3 years ago
10 POINTS ! PLEASE HELP !
ratelena [41]
The answer would be B
5 0
3 years ago
Read 2 more answers
There are about 1.4×109 cubic kilometers of water on Earth. About 2.5% of the water is fresh water. How much fresh water is on E
Sveta_85 [38]

Answer:

Amount of fresh water = 3.5 * 10^7 cubic kilometers

Step-by-step explanation:

Given the following

Total water on earth = 1.4×10^9 cubic kilometers

If 2.5% of it is fresh water

Amount of fresh water = 2.5% of 1.4×10^9

Amount of fresh water = 0.025 * 1.4×10^9

Amount of fresh water = 0.035 * 10^9

Amount of fresh water = 3.5 * 10^7 cubic kilometers

8 0
3 years ago
Please help I don't understand the math language
NNADVOKAT [17]

Answer:

19

Step-by-step explanation:

3x+4 while x is 5 means (3*5)+4 so 15+4=19

If that's not what you wanted I am sorry.

8 0
3 years ago
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In rhombus MOTH, angle HTM=(5x+6) degrees. If angle HMO=(12x-6)degrees, what is angle HMO?
forsale [732]

Answer:

m∠HMO=102°

Step-by-step explanation:

we know that

In a Rhombus the diagonals bisect the angles and opposite angles are equal

In this problem

Angles HMO and HTO are opposite angles

m∠HMO=m∠HTO

m∠HTM=(1/2)m∠HMO ----> because the diagonals bisect the angles and opposite angles are congruent

substitute the values

(5x+6)\°=(1/2)(12x-6)\°

solve for x

10x+12=12x-6\\12x-10x=12+6\\2x=18\\x=9

<em>Find the measure of angle HMO</em>

m∠HMO=(12x-6)°

substitute the value of x

m∠HMO=(12(9)-6)=102°

see the attached figure to better understand the problem

5 0
3 years ago
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