Answer:
The sun would appear to move more slowly across Mercury's sky.
Explanation:
This is because, the time it takes to do one spin or revolution on Mercury is 176 days (which is its period), whereas, the time it takes to do one spin or revolution on the Earth is 1 day.
Since the angular speed ω = 2π/T where T = period
So on Mercury, T' = 176days = 176 days × 24 hr/day × 60 min/hr × 60 s/min = 15,206,400 s
So, ω' = 2π/T'
= 2π/15,206,400 s
= 4.132 × 10⁻⁷ rad/s
So on Earth, T" = 1 day = 1 day × 24 hr/day × 60 min/hr × 60 s/min = 86,400 s
So, ω" = 2π/T"
= 2π/86,400 s
= 7.272 × 10⁻⁵ rad/s
Since ω' = 4.132 × 10⁻⁷ rad/s << ω" = 7.272 × 10⁻⁵ rad/s, <u>the sun would appear to move more slowly across Mercury's sky.</u>
Answer:
F. 1, 1
G. 1
Explanation:
When you work out how many there are of each thing, the numbers that were already in there equal each other, do you just need to add ones in the other blanks.
Answer:
There are 10 moles of copper(II)sulfate.
Explanation:
We know that molarity is a concentration measure that expresses the moles of solute per liter of solution: in this case, being 1.30 molar, there are 1.30 moles of solute in 1 liter of solution. We solve with the following simple rule of three:
1 L solution-----2 moles of copper(II)sulfate
5 L solution----x= (5 L solution x 2 moles of copper(II)sulfate)/1 L solution
<em>x= 10 moles of copper(II)sulfate</em>
Answer:
The maximum kinetic energy of electron is = 2.93 × 
Joule
Explanation:
We know that total energy
------------ (1)
Here h = plank's constant = 6.62 × 
J s
c = speed of light = 3 × 
= 261 nm = 261 × 
m
Put all these values in equation (1) we get
E = 7.6 × J
We know that
Total energy = Energy to remove an electron + K.E of electron
Energy to remove an electron = 
Energy to remove an electron = 4.67 × J
K.E of electron = Total energy - Energy to remove an electron
K.E of electron = 7.6 × - 4.67 ×
K.E of electron = 2.93 × Joule
Therefore the maximum kinetic energy of electron is = 2.93 × Joule
<span>When M(OH)2 dissolves we have
M(OH)2 which produces M2+ and 2OHâ’
pH + pOH=14
At ph =7; we have
7+pOH=14
pOH=14â’7 = 7
Then [OHâ’]=10^(â’pOH)
[OH-] = 10^(-7) = 1* 10^(-7)
At ph = 10. We have,
pOH = 4. And [OH-] = 10^(-4) = 1 * 10^(-4)
Finally ph = 14. We have, pOH = 0
And then [OH-] = 10^(-0) -----anything raised to zero power is 1, but (-0)...
So [OH-] = 1</span>
