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irinina [24]
2 years ago
10

Quest

Chemistry
2 answers:
Sever21 [200]2 years ago
8 0

Answer:

D. An acid accepts an electron pair from a base.

Explanation:

acorroding to lewis

  • an acid is a compound which accepts a pair of electrons from base .

  • a base is a compound which donates a pair of electron to acid .
stepladder [879]2 years ago
3 0
I think the answer is D !!!!!!!!
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Give the structures of both 1,2 and 1,4 adducts resulting from reaction of 1 equivalent of hcl with 1,3-pentadiene
GrogVix [38]

1,3-pentadiene has two double bonds which are conjugated, which undergo electrophilic addition reaction on reacting with HCl.

The structure of 1,3-pentadiene is shown in the image.

When strong acid such as HCl reacts with 1,3-pentadiene, the electrophilic addition reaction can occur either on double bond at 1,2-position or at 3,4-position. The reaction that occurs is shown in the image.

3 0
3 years ago
Chemistry Question! 20 Points!
Delvig [45]

Answer:

A

Explanation:

I guess it's a, because nuclear decay is likely to occur when either the mass or atomic number is greater than 83.

7 0
3 years ago
3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m
IrinaK [193]

Answer:

49.45~%

Explanation:

In this case, we have to start with the <u>chemical reaction</u>:

C_6H_1_2O~->~C_6H_1_0~+~H_2O

So, if we start with <u>10 mol of cyclohexanol</u> (C_6H_1_2O) we will obtain 10 mol of cyclohexanol (C_6H_1_0). So, we can calculate the grams of cyclohexanol if we<u> calculate the molar mass:</u>

(6*12)+(10*1)=82~g/mol

With this value we can calculate the grams:

10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0

Now, we have as a product 500 mL of C_6H_1_0. If we use the <u>density value</u> (0.811 g/mL). We can calculate the grams of product:

500~mL\frac{0.811~g}{1~mL}=405.5~g

Finally, with these values we can calculate the <u>yield</u>:

%~=~\frac{405.5}{820}x100~=~49.45%%= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

6 0
3 years ago
How many moles of nacl are required to make 250 ml of a 3.00 m solution?
choli [55]
The molarity is calculated using the following rule:
molarity = number of moles of solvent / volume of solution (in liters)

We have the volume of solution = 250 ml = 0.25 liters and the molarity = 3 m

Substituting in the equation, we get:
3 = number of moles / 0.25
number of moles = 3 x 0.25 = 0.75 moles
4 0
3 years ago
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