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3 years ago

Given the measure of arc dc is 120 the measure of arc ADC is?

Mathematics

2 answers:

Volgvan3 years ago

6 0

The answer would be 120

slavikrds [6]3 years ago

3 0

Answer:

120°

Step-by-step explanation:

The arc ABC is twice that of the angle created at D. This is the central angle theorem extension.

So we can say that arc ABC = 2* 120 = 240

We know total circle angle is 360 degrees so, arc ADC + arc ABC = 360

Hence,

arc ADC + 240 = 360

arc ADC = 360 - 240 = 120

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How to solve 4x+6y less than or equal to 120

yaroslaw [1]

120 - 4 - 6 = ( that is the process, you ca find the answer)

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2 years ago

M, N, and P divide AB into four equal parts. Prove that vector OP=1/4(vector OA+3*vectorOB) for any point O

Mademuasel [1]

Answer:d

Step-by-step explanation:

4 0

3 years ago

What divided by 9 equals 5

den301095 [7]

9 divided by 1.8 is the answer

8 0

4 years ago

Read 2 more answers

Jaida was grocery shopping for easter dinner, she got 7 lb Spanish serano ham for $50, 5 lbs of russet potatoes for $5 and a bag

Marrrta [24]

Answer: $61.48

Step-by-step explanation:

First, let’s find her cost before tax by adding everything she bought together.

50+5+3=58

Then, find the cost of sales tax.

Convert 6% to a decimal

6/100=0.06

Multiply the total cost by the decimal

58*0.06=3.48

Add the tax and total cost together

58+3.48=61.48

So the total cost with tax is $61.48

Hope this helped!

8 0

4 years ago

Help i dont understand how to complete this

Luda [366]

Answer: Josh = 19.8 hours, Danny = 10.8 hours

Step-by-step explanation:

$Josh: \dfrac{1}{x+9}\\\\\\Danny: \dfrac{1}{x}\\\\\\Together: \dfrac{1}{7}\\\\\\Josh\quad + \quad Danny\quad =\quad Together\\\dfrac{1}{x+9}\quad +\qquad \dfrac{1}{x}\qquad = \qquad \dfrac{1}{7}\\\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (x+9)(x)(7)}}\\\\7(x) + 7(x+9)=x(x+9)\\7x + 7x + 63 = x^2+9x\\14x+63=x^2+9x\\0=x^2-5x-63\\\\\\\underline{\text{Use the quadratic formula to solve for x: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(1)(-63)}}{2(1)}\\\\\\.\quad =\dfrac{5\pm\sqrt{25+252}}{2}\\\\\\.\quad =\dfrac{5\pm\sqrt{277}}{2}\\\\\\.\quad =\dfrac{5\pm 16.6}{2}\\\\\\x =\dfrac{5+16.6}{2}\qquad x=\dfrac{5-16.6}{2}\\\\\\x=\dfrac{21.6}{2}\qquad \qquad x=\dfrac{-11.6}{2}\\\\\\x=10.8 \qquad \qquad x=-5.8$

Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8

Josh: x + 9 --> 10.8 + 9 = 19.8

Danny: x --> 10.8

****************************************************************************************

2a) k = 9.45 & 0.55

2b) x = 3/2

2c) x = 2/3 (x = -1 is an extraneous solution so is not valid)

2d) No Solution (x = 1 is an extraneous solution so is not valid)

Here is the work for 2a. Follow this format for b, c, & d

$\dfrac{3}{k^2-8x+12}=\dfrac{k}{k-2}-\dfrac{4}{k-6}\\\\\text{Since the denominator cannot equal zero, then } k \neq2\ and\ k\neq6\\\text{If either of the solutions are 2 or 6, then that solution needs to be crossed out}\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (k-2)(k-6)}}\\\\3 = k(k-6)-4(k-2)\\3=k^2-6k-4k+8\\0=k^2-10k+5\\\\\\\underline{\text{Use the quadratic formula to solve for k}}$

$x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(1)(5)}}{2(1)}\\\\\\.\quad =\dfrac{10\pm\sqrt{100-20}}{2}\\\\\\.\quad =\dfrac{10\pm\sqrt{80}}{2}\\\\\\.\quad =\dfrac{10\pm8.9}{2}\\\\\\x=\dfrac{10+8.9}{2}\qquad x=\dfrac{10-8.9}{2}\\\\\\x=\dfrac{18.9}{2}\qquad x=\dfrac{1.1}{2}\\\\\\x=9.45\qquad x=0.55\\\\\\\text{Both answers are valid!}$

8 0

3 years ago