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rewona [7]
3 years ago
15

Nahum and Ahlayah are buying concert tickets from a website. There is a 20% service fee for every ticket bought from the site. I

f the cost of 2 tickets, including the service fee was $72 what was the cost of each ticket before applting the service fee? Explain Please
Mathematics
1 answer:
KengaRu [80]3 years ago
5 0
Dam pretty sure its 5.26%
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larisa86 [58]
I thinks it’s line 5
4 0
3 years ago
PLZZZZ HELLPP  50 POINTS TO WHO CAN ANSWER CORRECTLY
finlep [7]
For this case we are going to assume that Nina wrote:
 3/4 (1440) + 295.25 + (-33.50).
 The expression is correct since we have:
 ticket sales were three-fourths as much as yesterday. That means
 3/4 (1440)
 food sales were down by $ 33.50, that means:
 295.25 + (-33.50)
 Therefore, today's sales were:
 3/4 (1440) + 295.25 + (-33.50).
 answer
 Nina's expression is correct
5 0
3 years ago
Read 2 more answers
I need help please! I’ll give brainliest, thank you!
Alex777 [14]
A) domain: [ -5 5 ] range: [ -10 -2 ]
b) y intercept: -2 x intercept: -2 2
c) y= -2
d) x= -2 x= 2
e) None
4 0
2 years ago
3 + x = 18 please help!!!!!!!!!!
Ierofanga [76]

Answer:

X=15

all you have to do is subtract 3 from 18 to get x

6 0
3 years ago
Read 2 more answers
Suppose that we want to test the hypothesis with a significance level (alpha) of .05 that the climate has changed since industri
saw5 [17]

Answer: we reject the initial claim

(50. 3802, 51.6198)

Step-by-step explanation:

A)

The initial statement is that the mean temperature throughout history is 50°

This is the null hypothesis and it is denoted as H'

H': u = 50.

After taking a sample of 40 years, we realized that the mean temperature is 51°.

This is the alternative hypothesis, in contradiction to the alternative.

The alternative hypothesis is denoted as H1

H1: u > 50 ( upper tailed).

Sample size (n) = 40

Sample mean (x) = 51

Population standard deviation (σ) = 2

We use a z test to get the value of the test statistics.

We are using a z test because sample size is greater than 30 ( n = 40) and population standard deviation is given.

Z score = x - u/ (σ/√n)

Z score = 51 - 50 / (2/√40)

Z score = 1 / 0.3162

Z score = 3.16

Our level of significance is 5%, and the critical value at this level of significance is 1.645.

By comparing the z score relative to the critical value, since our z score is greater than 1.645, it implies that we are in the rejection region hence we reject the initial claim.

B)

We are to construct a 95% confidence interval for population mean temperature.

For upper limit

u = x + Zα/2 ×(σ/√n)

Where Zα/2 = 1.96 which is the critical value for a two tailed test at 5% level of significance.

For upper limit, we have that

u = 51 + 1.96 × (2/√40)

u = 51 + 1.96 (0.3162)

u = 51 + 0.6198

u = 51.6198.

For lower limit, we have that

u = 51 - 1.96 × (2/√40)

u = 51 - 1.96 (0.3162)

u = 51 - 0.6198

u = 50. 3802.

Hence the 95% confidence level for mean temperature is given as (50. 3802°, 51.6198°)

7 0
3 years ago
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