Answer:
The solution is 
. Fourth option
Explanation:
Solve for x:
Move all the terms from the right to the left side of the equation, a zero in the right side:
Join all like terms:
The general form of the quadratic equation is:
Solve the quadratic equation by using the formula:
In our equation: a=1, b=-2, c=-46
Substituting into the formula:
Since 188=4*47
Take the square root of 4:
Divide by 2:
First option: Incorrect. The answer does not match
Second option: Incorrect. The answer does not match
Third option: Incorrect. The answer does not match
Fourth option: Correct. The answer matches exactly this option
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90
Answer:
0.84
Step-by-step explanation:
Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:
P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95
We are to find out P(A'UB)
We have
![P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84](https://tex.z-dn.net/?f=P%28A%27UB%29%20%3D%20P%28A%27%29%2BP%28B%29-P%28A%27%20%5Cbigcap%20B%29%5C%5C%3D%201-P%28A%29%20%2BP%28B%29-%5BP%28B%29-P%28A%20%5Cbigcap%20B%29%5D%5C%5C%3D%201-0.86%2B0.79-P%28B%29%2B%5Btex%5DP%28A%27UB%29%3D0.14%2B0.79-0.79%2B0.70%5C%5C%3D0.84)
P(A \bigcap B)[/tex]
K = 100/9, or approximately 11.111
