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Serhud [2]
3 years ago
10

If friction is ignored and the ball is dropped, it experiences a gain in ____ and a decrease in ___. Question 8 options: kinetic

energy; potential energy potential energy; kinetic energy thermal energy; potential energy potential energy; thermal energy
Physics
1 answer:
seropon [69]3 years ago
7 0

Answer:

My answer is when the ball is going it experience kinetic energy which is the energy of a moving object while when the ball has stopped then it will have potential energy which means it's at rest so for the ball not to experience friction then there is a gain in kinetic energy and decrease in potential energy.

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You walk 12.0 m West and then 4.00 m south. What is your displacement?​
Karo-lina-s [1.5K]

Answer:

12.6 (3 sig. fig.)

Explanation:

(12^2 + 4^2)^1/2 = 12.6 (3 sig. fig.)

7 0
3 years ago
Two homogeneous bodies of the same volume
lord [1]

Answer:

No, it is not necessary for them to have same mass.

Explanation:

Let both bodies have a density d1 and d2 respectively.

Since their volumes are equal V1 = V2

we know that, https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D

Hence, d1 =  and d2 =    

Taking the ratio of densities,we get

This implies that unless the bodies have same densities, the mass of the two bodies will not be same.

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3 years ago
If the battery of your phone can provide 2 mA of current to your phone and holds a charge of 130 C, how long will it take a full
Naya [18.7K]

Answer: 65000 seconds

Explanation:

Given that,

Current (I) = 2 mA

(Since 1 mA = 1 x 10^-3A

2 mA = 2 x 10^-3A)

Charge (Q) = 130 C

Time taken for a fully charged phone to die (T) = ?

Recall that the charge is the product of current and time taken.

i.e Q = I x T

130C = 2 x 10^-3A x T

T = 130C / (2 x 10^-3A)

T = 65000 seconds (time will be in seconds because seconds is the unit of time)

Thus, it will take a fully charged phone 65000 seconds to die

5 0
3 years ago
A land breeze forms when:
victus00 [196]

Explanation:

Its D. The warm air from the land moves towards the water

7 0
3 years ago
Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45 m diamete
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Answer:

In m/s^2:

a=11.3778 m/s^2

In units of g:

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Explanation:

Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.

a=\frac{v^2}{r}

where:

v is the speed

r is the radius

Now,

a=\frac{16^2}{45/2}\\ a=11.3778 m/s^2

In g units:

a=\frac{11.3778\ g}{9.8}\\ a=1.161\ g

7 0
3 years ago
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