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podryga [215]
3 years ago
9

(NEED HELP! +28pts and BRAINLIEST) The total energy output of a star per second is called ________. Select all that apply.

Physics
2 answers:
topjm [15]3 years ago
8 0

Answer:

The answer would be B.) Luminosity.

Explanation:

The luminosity of a star is basically, as the question says, the total energy output of a star per second. The luminosity is also the brightness of a star. If a star has a lot of energy, the star would be bright.

Alekssandra [29.7K]3 years ago
3 0

Answer:

luminosity

Explanation:

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Virty [35]

Answer:

18.24 seconds

Explanation:

First you convert the km/h to m/s, 70km/h=(175/9)m/s,85km/h=(425/18)m/s.

You know it took 10 seconds for the police to reach 85 km/h. Calculate the distance that the car is ahead of the police (175/9)*10=1750/9m. Then by divide 1750/9 with 425/18, you will get the value 8.24. Add the 10 seconds with the 8.24 you will get 18.24 sec which is the total time.

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How fast is the sixth cosmic velocity?
denpristay [2]
<span>25,000 miles per hour

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Which of these events is an example of resonance?
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An opera singer breaks a thin glass with only the use of her high frequency voice
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3 years ago
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A satellite is in a circular orbit 21000 km above the Earth’s surface; i.e., it moves on a circular path under the influence of
mina [271]

Answer:

(orbital speed of the satellite) V₀ = 3.818 km

Time (t) = 4.5 × 10⁴s

Explanation:

Given that:

The radius of the Earth is 6.37 × 10⁶ m;    &

the acceleration of gravity at the satellite’s altitude is 0.532655 m/s

We can calculate the orbital speed of the satellite by using the formula:

Orbital Speed (V₀) = √(r × g)

radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m

                                  = (2.1 × 10⁷ + 6.37 × 10⁶) m

                                  = 27370000

                                  = 2.737 × 10⁷m

Orbital Speed (V₀) = √(r × g)

Orbital Speed (V₀) = √(2.737 × 10⁷  × 0.532655 )

                              = 3818.215

                              = 3.818 × 10³

                             = 3.818 Km

To find the time it takes to complete one orbit around the Earth; we use the formula:

Time (t) = 2 π × \frac{r}{V_o}

            = 2 × 3.14 × \frac{2.737*10^7}{3.818*10^3}

            = 45019.28

            = 4.5 × 10 ⁴ s

6 0
3 years ago
An intergalactic rock star bangs his drum every 1.50 s. A person on earth measures that the time between beats is 2.70 s. How fa
sineoko [7]

Answer:

v = 83.1 % of speed of light

Explanation:

given,

T_e is the earth time = 2.7 s

T_s is the ship time = 1.5 s

we know,

T_s = T_e \times \gamma

where c is the speed of light

v is the speed of the rock star moving

T_s = T_e\times \sqrt{1-\dfrac{v^2}{c^2}}

1.5= 2.7\times \sqrt{1-\dfrac{v^2}{c^2}}

\sqrt{1-\dfrac{v^2}{c^2}} =0.556

squaring both side

1-\dfrac{v^2}{c^2}=0.3086

v^2=0.6914c^2

v = 0.831 c

v = 83.1 % of speed of light

7 0
3 years ago
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