Orbital fracture is caused by impact to the face that may be sourced from low, mid, or upper. It can be treated by lots of medical practices with the goal of restoring the aesthetics or physiologic appearance of the area of injury. The bone that is most commonly affected is the eye socket bone.
Red has a longer wavelength than yellow
Given:
object = 20kg
terminal speed of object = 80 m/s
According to the problem, drag force is proportional to speed, so Fd = kv ; k is some constant
At terminal velocity Vt: Fg = Fdmg = kVtk = mg / Vt = (20.0)(9.8)/(80.0) = 2.45 kg/s
<span>Fd = kv = 2.45v</span>
Fd = 2.45 (30.0) = 73.5 N
The free-body diagram of your question is; 2 downward forces (253 kg mass of barbell & 133 kg body mass of Kurlovich) acting together on a point supported by 2 upward forces as normal forces exerted by Kurlovich's feet.
Solving the normal forces exerted by 2 feet :
Summation of Forces Vertical = 0
2 Dowwnard Forces = 2 Upward Forces (2F)
253 + 133 = 2F
2F = 386 Kgs
F = 386 / 2
F = 193 Kgs (Normal Force Exerted by Each Foot)
Answer:
The circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.
Explanation:
Since the magnetic field, B points in my direction and the current, I is moving in a clockwise direction, the current is always perpendicular to the magnetic field and will thus experience a constant force, F = BILsinФ where Ф is the angle between B and L.
Since the magnetic field is in my direction, it is perpendicular to the plane of the circular loop and thus perpendicular to L where L = length of circular loop. Thus Ф = 90° and F = BILsin90° = BIL
According to Fleming's left-hand rule, the fore finger representing the magnetic field, the middle finger represent in the current and the thumb representing the direction of force on the circular loop.
At each point on the circular loop, the force is always directed towards the center of the loop and thus tends to compress it.
<u>So, the circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.</u>