You drop your cell phone. Prior to hitting the ground, the phone's kinetic energy will ________ and its potential energy will __
1 answer:
Answer:
The kinetic energy of the phone would increase. The gravitational potential energy of the phone would decrease.
Explanation:
The kinetic energy of an object is proportional to the square of the speed of that object. If air resistance is negligible, the phone would accelerate under gravitational pull and speed up. Hence, the kinetic energy of the phone would increase.
The gravitational field near the surface of the earth is approximately constant. Hence, the gravitational potential energy of the phone would be proportional to its height. As the phone approaches the ground, the height of the phone becomes lower and the gravitational potential energy of the phone would decrease.
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Answer:
Direction 1: Force is Non-zero and Not- constant
Direction 2: Force is Non-zero but constant
Explanation:
Given:
The picture of the map is attached. ( Missing from the question ).
Find:
The effect of force as it travels along each direction.
Solution:
- We know the relationship between change in potential and the force acting on the charge particle is given by:
F = - q*dV/ dr
Where,
q : Charge of the particle
V : Volt potential
dV/dr : Potential difference along a direction.
Direction 1:
- The color code of the map changes as the particle moves along this direction. Each color code represents a potential difference. So as the particle moves between different potential difference then according to the relationship given above The force varies along varies as particle moves from one color to another. Hence, a non zero force but not constant.
Direction 2:
- In the direction 2, the charged particle moves along the same color. The potential difference for each color is constant. Hence, according to the relationship of potential difference and force. If potential difference is constant then the Electrostatic Force on the charge is also constant. Hence, Force is non-zero and constant.
Answer:
a)
b)
Explanation:
Given:
mass of ball,
initial speed of the ball,
mass of the person,
a)
Using the conservation of linear momentum:
When the person catches the ball, assuming that the person catches it with an impact without absorbing the shock.
b)
When the ball hits the person and bounces off with the velocity of .
Using the conservation of linear momentum:
where:
final speed of the ball after collision
final speed of the person after collision
initial velocity of the person = 0
putting the respective values in the above eq.