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3 years ago

If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point (5, 6).

Mathematics

2 answers:

N76 [4]3 years ago

8 0

Answer:

False

Step-by-step explanation:

(5-2)²+(6-6)²=3²+0=9 and not 4

Salsk061 [2.6K]3 years ago

5 0

Hello,

False

(5-2)²+(6-6)²=3²+0=9 and not 4

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Solutions to 2-variable equations

Galina-37 [17]

Answer:

B) only (-3 , 3)

Step-by-step explanation:

y = -3x - 6

(-4,4) y = -3 x (-4) - 6 = 12 - 6 = 6 .... incorrect

(-3,3) y = (-3) x (-3) - 6 = 9 - 6 = 3 ..... correct

8 0

3 years ago

Read 2 more answers

The price of Stock A at 9 A.M. was $15.03. Since then, the price has been increasing at the rate of $0.05 each hour. At noon

irina1246 [14]

After 1.842 hours the price of Stock A and Stock B will be the same using a set of linear equations.

A grouping of one or more linear equations containing the same variables is known as a system of linear equations.

For Stock A :

The initial price = $15.03

The rate of increase = $0.05

For Stock B :

The rate of decrease = $15.53

The rate of decrease per hour = $0.13

Then the price of stock A at noon will be:

$ 15.03 + $ (0.05 × 3) = $ 15.03 + $ 0.15 = $15.18

The period of time during which the stock price will remain constant:

15.18 + 0.05t = 15.53 - 0.14t

Simplifying the terms we get,

0.05t + 0.14t = 15.53 - 15.18

0.19t = 0.35

t = (0.35 ÷ 0.19) hours

t = 1.842 hours

Therefore, the stocks will be of equal price after 1.842 hours.

Learn more about stocks here:

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3 0

1 year ago

TIMED QUIZ HALPThe table represents a linear function.

alina1380 [7]

Answer:

-6

Step-by-step explanation:

(y2-y1) / (x2-x1)

(-16-(-10)) / (2-1)

(-6) / (1)

= -6

Take any two points in the graph and put them into the formula.

6 0

3 years ago

Read 2 more answers

Solve −2x2 − 16x − 44 = 0.

Mazyrski [523]

I hope this helps you

3 0

4 years ago

Read 2 more answers

Consider a binomial experiment with 15 trials and probability 0.35 of success on a single trial.

DedPeter [7]

Answer:

$P(X = 10 ) = 0.0096$

$P(X = 10 ) = 0.0085$

Option A is correct

Step-by-step explanation:

From the question we are told that

The sample size is n = 15

The probability of success is $p = 0.35$

The number of success we are considering is r = 10

Now the probability of failure is mathematically evaluated as

$q = 1- p$

substituting value

$q = 1- 0.35$

$q = 0.65$

Now using the binomial distribution to find the probability of exactly 10 successes we have that

$P(X = r ) = [\left n } \atop {r}} \right. ] * p^r * q^{n- r}$

substituting values

$P(X = 10 ) = [\left 15 } \atop {10}} \right. ] * p^{10}* q^{15- 10}$

Where $[\left 15 } \atop {10}} \right. ]$ mean 15 combination 10 which is evaluated with a calculator to obtain

$[\left 15 } \atop {10}} \right. ] = 3003$

$P(X = 10 ) = 3003 * 0.35 ^{10}* 0.65^{15- 10}$

$P(X = 10 ) = 0.0096$

Now using the normal distribution to approximate the probability of exactly 10 successes, we have that

$P(X = r ) = P( r < X < r )$

Applying continuity correction

$P(X = r ) = P( r -0.5 < X < r +0.5)$

substituting values

$P(X = 10) = P( 10-0.5 < X < 10+0.5)$

$P(X = 10 ) = P( 9.5 < X < 10.5)$

Standardizing

$P(X = r ) = P( \frac{9.5 - \mu }{\sigma } < \frac{X - \mu }{\sigma } < \frac{10.5 - \mu}{\sigma } )$

The where $\mu$ is the mean which is mathematically represented as

$\mu = n * p$

substituting values

$\mu = 15 * 0.35$

$\mu = 5.25$

The standard deviation is evaluated as

$\sigma = \sqrt{n * p * q }$

substituting values

$\sigma = \sqrt{15 * 0.35 * 0.65 }$

$\sigma = 1.8473$

Thus

$P(X = 10 ) = P( \frac{9.5 - 5.25 }{1.8473 } < \frac{X - 5.25 }{1.8473 } < \frac{10.5 - 5.25}{1.8473 } )$

$P(X = 10 ) = P( 2.30 < Z < 2.842 )$

$P(X = 10 ) = P(Z < 2.842 ) - P(Z < 2.30 )$

From the normal distribution table we obtain the $P(Z < 2.841)$ as

$P(Z < 2.841) = 0.99775$

And the $P(Z < 2.30)$

$P(Z < 2.30) = 0.98928$

There value can also be obtained from a probability of z calculator at (Calculator dot net website)

$P(X = 10) = 0.99775 - 0.98928$

$P(X = 10 ) = 0.0085$

Looking at the calculated values for question a and b we see that the values are fairly different.

8 0

4 years ago