What grade are you in I’m in 9th ;-;
Answer:
33.95 grams of NaN3
Explanation:
Number of moles of NaN3 = mass (m)/MW = m/65 mole
I mole of NaN3 requires 22.4L air bag
m/65 mole of NaN3 required 11.7L
22.4m/65 = 11.7
22.4m = 65×11.7
22.4m = 760.5
m = 760.5/22.4 = 33.95grams of NaN3
<h3>
Answer:</h3>
3.342 x 10^24 molecules of water
<h3>
Explanation:</h3>
Given;
Mass of water = 100.0 g
Required to determine the number of molecules in 100.0 g of water
Using Avogadro's constant
1 mole of a compound contains 6.022 × 10^22 molecules
Thus;
1 mole of H₂O contains 6.022 × 10^23 molecules
But;
1 mole = 18.02 g/mol
Therefore;
18.02 g of water contains 6.022 × 10^23 molecules
100.0 g of water will have;
= (100. 0 g ×6.022 × 10^23 molecules) ÷ 18.02
= 3.342 x 10^24 molecules
∆H = mc∆T
c = specific heat capacity
c of water = 4200 J/kg °C
∆H = 1 * 4200 * (100°C - 25°C)
∆H = 315000J
∆H = 315 KJ
