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zzz [600]
3 years ago
15

Enter the net ionic equation for this reaction. Express your answer as a net ionic equation. Identify all of the phases in your

answer. 2HCl(aq)+Ca(OH)2(aq) → 2H2O(l)+CaCl2(aq)
Chemistry
1 answer:
Lisa [10]3 years ago
6 0

Answer:

2H+(aq) + 2OH-(aq) → 2H2O(l)

Explanation:

Step 1: The balanced equation

2HCl(aq)+Ca(OH)2(aq) → 2H2O(l)+CaCl2(aq)

This equation is balanced, we do not have the change any coefficients.

Step 2: The netionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.

2H+(aq) + 2Cl-(aq) + Ca^2+(aq) + 2OH-(aq) → 2H2O(l) + Ca^2+(aq) + 2Cl-(aq)

After canceling those spectator ions in both side, look like this:

2H+(aq) + 2OH-(aq) → 2H2O(l)

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3 years ago
What is the chemical formula for Sodium Floride?
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Obtain the valence shell configuration of Al and S from their positions in the periodic table.
lutik1710 [3]

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3 years ago
Which isotope will spontaneously decay and emit particles with a charge of +2?
VikaD [51]

Answer: The correct option is 4.

Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:

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_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

2) Beta-minus decay: It is a decay in which a beta particle is released. The  beta particle released has a mass number of 0 and a charge of (-1).

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

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For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form _{25}^{53}\textrm{Mn}

_{26}^{53}\textrm{Fe}\rightarrow _{25}^{53}\textrm{Mn}+_{+1}^0\beta

Option 2: This nuclei will undergo beta-minus decay process to form _{80}^{198}\textrm{Hg}

_{79}^{198}\textrm{Au}\rightarrow _{80}^{198}\textrm{Hg}+_{-1}^0\beta

Option 3: This nuclei will undergo a beta minus decay process to form _{56}^{137}\textrm{Ba}

_{55}^{137}\textrm{Cs}\rightarrow _{56}^{137}\textrm{Ba}+_{-1}^0\beta

Option 4: This nuclei will undergo an alpha decay process to form _{85}^{216}\textrm{At}

_{87}^{220}\textrm{Fr}\rightarrow _{85}^{216}\textrm{At}+_2^4\alpha

Hence, the correct option is 4.

7 0
4 years ago
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