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2.61 kilojoules of heat would be liberated by the condensation of 5.00 g of acetone
Explanation:
To convert grams into moles
We have 5.00 g acetone
Heat liberated = moles heat of vapourization
=0.0861 mol x 30.3 kJ/mol
= 2.61 kJ
Therefore, 2.61 kilojoules of heat would be liberated by the condensation of 5.00 g of acetone
Answer:
1.95g of Mg(OH)2 are needed
Explanation:
Mg(OH)2 reacts with HCl as follows:
Mg(OH)2 + 2 HCl → MgCl2 + 2H2O
<em>Where 1 mole of Mg(OH)2 reacts with 2 moles of HCl</em>
To solve this question we must find the moles of acid. Then, with the chemical equation we can find the moles of Mg(OH)2 and its mass:
<em>Moles HCl:</em>
158mL = 0.158L * (0.106mol / L) = 0.01675 moles HCl
<em>Moles Mg(OH)2:</em>
0.01675 moles HCl * (2mol Mg(OH)2 / 1mol HCl) = 0.3350 moles Mg(OH)2
<em>Mass Mg(OH)2 -Molar mass: 58.3197g/mol-</em>
0.3350 moles Mg(OH)2 * (58.3197g / mol) =
<h3>1.95g of Mg(OH)2 are needed</h3>
Answer: Carbon-14 decays quickly leaving the amount too small to measure.
Explanation: