Ask question

Ask question

All categories

3 years ago

11

Fred's frog jumped 7 times as far as Al's frog. The two fogs jumped a total of 56 inches. How far did Fred's frog jump?

1 answer:

a_sh-v [17]3 years ago

4 0

Let us assume that Al’s frog jumped X inches.
Fred’s frog jumped 7X inches.
Total distance covered by both frogs is 56 inches.
Then X+7X=56
  8X=56
  X=56/8
  X=7
Fred’s frog jumped=7X inches <span>
  = 7*7 inches</span> <span>
  = 49 inches</span>

You might be interested in

I need help answering this question please!

iren [92.7K]

It is the graph of p is steeper than the graph of q.

7 0

3 years ago

What is the area of the regular octagon below?

pishuonlain [190]

9 plus How many sides nine times

3 0

3 years ago

Read 2 more answers

What is the answer For -6k Plus 7K

Furkat [3]

-6k+7k equals 1k.................................

8 0

3 years ago

What is the area of the kite below.

valentina_108 [34]

Answer:

girll how is this college math im in 8th grade and n learned this in 1st grade loll

Step-by-step explanation:

its 15 m I THINK DONT TAKE MY WORD ON IT but tytyty for the points

5 0

3 years ago

Maddie bought 3 2/3 yards of satin ribbon at the craft store. She wanted to make hair bows for the cheer squad. Each bow require

kotegsom [21]

Answer:

4

Step-by-step explanation:

Given that:

Total yards of satin bought by Maddie = $3\frac{2}{3}$ yards

Number of yards required make one ribbon = $\frac{2}{3}$ yards

To find:

Number of complete bows that can be made ?

Solution:

First of all, let us learn about converting the mixed fraction to fractional form.

Formula:

$a\dfrac{b}{c} = \dfrac{a\times c+b}{c}$

Therefore, total yards of satin bought by Maddie can be written in fractional form as:

$3\dfrac{2}{3} = \dfrac{3\times 3+2}{3} = \dfrac{11}{3}$

One hair bow requires $\frac{2}{3}$ yards of ribbon.

Number of hair bows that can be made, can be found by dividing the total ribbon length by ribbon required for making one hair bow.

Answer is:

$\dfrac{\frac{11}{3}}{\frac{2}{3}}\\\Rightarrow \dfrac{11\times 3}{2\times 3}\\\approx 4$

4 hair bows can be made.

4 0

2 years ago