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saw5 [17]
3 years ago
5

Why is MA always less than VR?​

Physics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

\boxed{ \bold{ \boxed{ \sf{see \: below}}}}

Explanation:

MA ( Mechanical Advantage ) is always less than VR ( Velocity Ratio ) because <u>MA</u><u> </u><u>is</u><u> </u><u>reduced</u><u> </u><u>by</u><u> </u><u>friction</u><u> </u><u>but</u><u> </u><u>VR</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>affected</u><u> </u><u>by</u><u> </u><u>friction</u><u>.</u>

Hope I helped!

Best regards! :D

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<h2>Answer:</h2>

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<h2>Explanation:</h2>

In Electromagnetic waves electric field produces magnetic field and vice versa. A moving magnet can produce electric current. Dynamo is the best example for it. In dynamo armature is rotated between the magnets which results in the development of electric field and hence an electric current is produced in it.

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To ancient peoples, why were planets special?
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Planets were like gods.

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A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling
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Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

      \frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}} ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

     \frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} ...... (2)

Now, equating both equations (1) and (2) as follows.

 Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} = Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}        

        \gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}

                    = \frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})

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4 0
2 years ago
A hot (70°C) lump of metal has a mass of 250 g and a specific heat of 0.25 cal/g⋅°C. John drops the metal into a 500-g calorimet
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Answer:

d. 37 °C

Explanation:

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c_{m} = specific heat of lump of metal  = 0.25 cal/g°C

T_{mi} = Initial temperature of lump of metal = 70 °C

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c_{w} = specific heat of water = 1 cal/g°C

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m_{c} = mass of calorimeter  = 500 g

c_{c} = specific heat of calorimeter = 0.10 cal/g°C

T_{ci} = Initial temperature of calorimeter = 20 °C

T_{f} = Final equilibrium temperature

Using conservation of heat

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6 0
3 years ago
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