If for a given pair of media CR

Physics

1 answer:

nika2105 [10]2 years ago

7 0

CR < CY < CB

<h3>Which factors affect the critical angle for a given pair of media?</h3>

The factors which affect the critical angle are

(a) The colour (or wavelength) of light

(b) The temperature

(i) Effect of colour of light: The critical angle for a pair of media is less for the violet light and more for the red light. Thus the critical angle increases with the increase in wavelength of light.

(ii) Effect of temperature: The critical angle increases with increase in temperature because on increasing temperature of medium, its refractive index decreases.

According to the question,

μ 1 sinCR =1

μ 2 sinCY =1

μ 3 sinCB =1

μ 1 > μ 2 and μ 2 > μ 3

⟹μ 1 > μ 2 > μ 3

CR < CY < CB

Thus,

The critical angle increases with the increase in wavelength of light.

Learn more about wavelength of light here:

brainly.com/question/27557868

#SPJ1

You might be interested in

Why are recessive traits not seen even though they are present in the alleles?

Rama09 [41]

Answer:

Explanation:. The vending machine holds 10 bags of pretzels and 8 packs of cheese crackers. Both the pretzels and crackers dispenseat 2 bags per hour. How many hours will elapse when there is the same number of snacks remaining in the vending machine? How many of each item will there be at this point?Equation1______________________________Equation2_______________________________Hours: ___________________________ Items: ____________________________What does each equation have n common? ______________________How does this affect the solution?

3 0

3 years ago

A 5000 kg truck traveling at 60 m/s stops in 5 seconds. How much friction was between the truck's tires and the ground?

oksano4ka [1.4K]

Answer:

60000N

Explanation:

acceleration is change in velocity

a =(v-u)/t where a is acceleration u is initial velocity and v is final velocity

a = (0-60)/5 = -60/5= - 12m/s^2

here minus sign shows that body is decelerating and force is force of friction Now f = ma here f is force of friction m is mass and a is acceleration

f= 5000×- 12= -60000N