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ddd [48]
3 years ago
15

50POINTS

Engineering
2 answers:
maxonik [38]3 years ago
7 0

Answer:

Ensure that all material and energy inputs and outputs are as inherently safe and benign as possible. Minimize the depletion of natural resources. Prevent waste. Develop and apply engineering solutions while being cognizant of local geography, aspirations, and cultures.Green engineering is the design, commercialization, and use of processes and products that minimize pollution, promote sustainability, and protect human health without sacrificing economic viability and efficiency.The goal of environmental engineering is to ensure that societal development and the use of water, land and air resources are sustainable. This goal is achieved by managing these resources so that environmental pollution and degradation is minimized.

Explanation:i helped

VikaD [51]3 years ago
3 0

Explanation:

One possible reason for this query could be the amount of trees per say would have to be cut down to construct the green engineering facilities. Another thing could be distance from other facilities. For example you wouldn't want a green engineering facility next to a fossil fuel burning facility. (That would be pointless.) Before comensing the green engineering process, you would also like to ask local officers for any enviornmental information that could be used during the making of this, since there may be endangered animals or things that could be affected by the construction. You would also not like a location near a big town or city since the noise or the very mild pollution may bother the locals.

#learnwithbrainly

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1. What is an op-amp? List the characteristics of an ideal op-amp
Alexus [3.1K]

Answer:

An opamp is an operation amplifier. It takes an input signal and amplifies it on the output side.

An ideal opamp should have infinite impedance at its input, infinite gain on the output, and zero impedance on the output

8 0
2 years ago
A compressor receives air at 290 K, 95 kPa and shaft work of 5.5 kW from a gasoline engine. It should deliver a mass flow rate o
aev [14]

Answer:

P2 = 3.9 MPa

Explanation:

Given that

T₁ = 290 K

P₁ = 95 KPa

Power P = 5.5 KW

mass flow rate  = 0.01 kg/s

solution

with the help of table A5

here air specific heat and adiabatic exponent is

Cp = 1.004 kJ/kg K

and k = 1.4

so

work rate will be

W = m × Cp × (T2 - T1)              ..........................1

here T2 = W ÷ ( m × Cp) + T1    

so T2 = 5.5 ÷ ( 0.001 × 1.004 ) + 290

T2 = 838 k

so final pressure will be here

P2 = P1 × (\frac{T2}{T1})^\frac{k}{k-1}        ..............2

P2 = 95 × (\frac{838}{290})^\frac{1.4}{1.4-1}

P2 = 3.9 MPa

3 0
2 years ago
According to the eNotes, a program that eliminates sales and promotions in an effort to minimize the bullwhip effect would be ca
Ilia_Sergeevich [38]

Options: True or false

Answer:True, it will be called CRMWRONGEDLP.

Explanation:eNotes was founded in 1998 by Brad Satoris and Alexander Bloomingdale, to enable and enhance the ability of students to solve assignments as given and other home works,eNote is also used by students to prepare effectively and efficiently for examinations.

Since its launch eNote has been a great source of educational materials for students who have gained a lot in the use of its materials.

bullwhip effect is a concept in supply chain, where forcasts causes the supply chain to be inefficient, it usually starts from retailers who raise concern of high demands.

CRMWRONGEDLP, is the program that minimizes the bullwhip effects according to eNote.

7 0
3 years ago
The car travels around the portion of a circular track having a radius of r = 500 ft such that when it is at point A it has a ve
stellarik [79]

Answer:

Explanation:

Given

velocity at A is v=4\ ft/s

For r=500\ ft

velocity is increasing at \dot{v}=0.004t\ ft/s^2

Tangential acceleration is given by

a_t=\frac{\mathrm{d} v}{\mathrm{d} t}

a_t=0.004t=\frac{\mathrm{d} v}{\mathrm{d} t}

\int 0.004tdt=\int dv

\int dv=\int 0.004tdt

v=0.002t^2+c

at t=0\ v=4\ ft/s

4=0.002\cdot 0+c

c=4\ ft/s

thus v=0.002t^2+4

Velocity in terms of Displacement is given by

v=\frac{\mathrm{d} s}{\mathrm{d} t}

\Rightarrow \int ds=\int \left ( 0.002t^2+4\right )dt

\Rightarrow s=\frac{0.002t^3}{3}+4t

When car has traveled \frac{3}{4} th of distance i.e.

s=\frac{3}{4}\times (2\pi r)=\frac{3\pi r}{2}

s=750\pi

750\pi =\frac{0.002t^3}{3}+4t

\Rightarrow \frac{0.002t^3}{3}+4t-2356.5=0

on solving we get t=139.23\ s

Thus velocity at t=139.23\ s

v=42.76\ s

(b)Acceleration when car has traveled three-fourth the way of track

normal acceleration a_n=\frac{v^2}{r}=\frac{(42.76)^2}{500}

a_n=3.658\ m/s^2

Tangential acceleration a_t at t=139.23\ s

a_t=0.556\ m/s^2

Net acceleration a_t=\sqrt{(a_n)^2+(a_t)^2}

a_n=\sqrt{(3.658)^2+(0.556)^2}

a_n=3.7\ m/s^2

   

8 0
3 years ago
Write a grammar for a language whose sentences start with an even and non-zero number of x’s, end with an odd number of z’s, and
sveta [45]

Answer:

GRAMMAR

S -> AB

A -> xxAyy | xxyy

B -> yyBzz | yz

EXPLANATION

A is for even number of x's followed by that number of y's

B is for odd number of y's followed by that number of z's

3 0
3 years ago
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