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alexira [117]
4 years ago
14

Question 3. Assign boston_under_10 and manila_under_10 to the percentage of rides that are less than 10 minutes in their respect

ive metropolitan areas. Use the height variables provided below in order to compute the percentages. Your solution should only use height variables, numbers, and mathematical operations. You should not access the tables boston and manila in any way.

Engineering
1 answer:
Sever21 [200]4 years ago
3 0

Answer:

Enter the following code  to get the required conditions for the answer.

boston_under_5_height = 1.2

manila_under_5_height = 0.6

boston_5_to_under_10_height = 3.2

manila_5_to_under_10_height = 1.4

boston_under_10 = boston_under_10 = 5*boston_under_5_height + 5*boston_5_to _under_10_height

manila_under_10 = manila_under_10 = 5*manila_under_5_height + 5*manila_5_to _under_10_height

Explanation:

Kindly note that question in complete as it belong to the topic of table manipulation and visualization topic. The question asks about the company called Uber and their data extraction from the website called movements.uber.com where data was extracted for 200,000 weekdays in the respective cities of Manila, Philippines and Boston, Massachusetts. Images attached contains the histograms generated for the rides in manila and boston.

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Steam enters an adiabatic turbine at 800 psia and9008F and leaves at a pressure of 40 psia. Determine themaximum amount of work
Naily [24]

Answer:

w_{out}=319.1\frac{BTU}{lbm}

Explanation:

Hello,

In this case, for the inlet stream, from the steam table, the specific enthalpy and entropy are:

h_1=1456.0\frac{BTU}{lbm} \ \ \ s_1=1.6413\frac{BTU}{lbm*R}

Next, for the liquid-vapor mixture at the outlet stream we need to compute its quality by taking into account that since the turbine is adiabatic, the entropy remains the same:

s_2=s_1

Thus, the liquid and liquid-vapor entropies are included to compute the quality:

x_2=\frac{s_2-s_f}{s_{fg}}=\frac{1.6313-0.39213}{1.28448}=0.965

Next, we compute the outlet enthalpy by considering the liquid and liquid-vapor enthalpies:

h_2=h_f+x_2h_f_g=236.14+0.965*933.69=1136.9\frac{BTU}{lbm}

Then, by using the first law of thermodynamics, the maximum specific work is computed via:

h_1=w_{out}+h_2\\\\w_{out}=h_1-h_2=1456.0\frac{BTU}{lbm}-1136.9\frac{BTU}{lbm}\\\\w_{out}=319.1\frac{BTU}{lbm}

Best regards.

3 0
3 years ago
Trent is designing the grounds for a massive outdoor skate park. He has no experience with skateboarding at all, and although he
alexandr1967 [171]

Answer:

I’m sorry I don’t understand this is there more steps?‍♀️

Explanation:

8 0
3 years ago
Read 2 more answers
Allura Red Moles
Ivanshal [37]

Answer:

Die of intoxication by water first

Explanation:

We assume that the weight of the man is 154.35 pounds which is 70 kg

LD50 water = 90g per kg

Maximum concentration = 90x70

= 6300grams

Convert grams to liters

6300/100

= 6.3 litres

From here we get amount of kool aid

6.3 x 1.97x10^-4

= 1.24x10^-3

= 1.24grams

1.24 grams is below 420 kool aid is lower than LD50 with about 6 grams for 1 kg (6x70kg = 420). So 420 is lethal dose. But 1.24 is less than this so the man has to die of water intoxication first.

8 0
3 years ago
which type of building construction can include materials with no fire-resistance ratings in limited quantities?
hammer [34]

The type of type of building construction can include materials with no fire-resistance ratings in limited quantities is type 2.

Although many buildings appear to be similar at first appearance, their cost and durability—particularly in an emergency—are affected by the underlying materials. Building codes categorize all structures into Types 1 through 5, and each Type discloses important details like fire-resistance.

Some contemporary structures are now stronger and less expensive to construct. Engineered wood and synthetic plastics, which burn readily, cause quick collapses and present significant risks for firefighters.

Type 1 constructions, which are the most fire-resistant buildings, are made of shielded steel and concrete because they can sustain high temperatures without collapsing. Type 5 constructions, on the other hand, are the least fire-resistant since they are built of flammable materials, are lightweight, and they burn out quickly. Type 2 constructions, modern structures with metal roofs and tilt-slab or reinforced masonry walls.

To know more about fire-resistance click on the link:

brainly.com/question/14447720

#SPJ4

6 0
1 year ago
A thick casting with a thermal diffusivity of 5 x 10-6 m2/s is initially at a uniform temperature of 150oC. One surface of the c
fredd [130]

Answer:

T_o = 141.81 ^0C

Explanation:

Given that;

Thermal diffusivity \alpha = 5 \times 10 ^{-6} m^2/s

Thermal conductivity k = 20 \ W/m.K

Heat transfer coefficient h = ( we are to assume the imposed surface temperature ) = 20 W/m².K

Initial temperature = 150 ° C = (150+273) K = 423 K

Then coolant temperature with which the casting is exposed to = 20° C = (20+273)K = 293 K

Time = 40 seconds

Length = 20mm = 0.02 m

The objective is to determine the  temperature at the surface  at a depth of 20 mm after 40 seconds.

Bi = \dfrac{hL}{k}

Bi = \dfrac{20*0.02}{20}

Bi == 0.02

\tau = \dfrac{\alpha t}{L^2}

\tau=  \dfrac{5*10^{-6 }* 40}{0.020^2}

\tau = 0.5

For a wall at 0.2 Bi

A_1 = 1.0311

\lambda _1 = 0.4328

Therefore;

\dfrac{T_o - T_{\infty}}{T_i - T_{\infty}}= A_1 e ^{-( \lambda_1^2 \ \tau)

\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.438^2 \times 0.5 )

\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.0959 )

\dfrac{T_o - 293 }{130}= 1.0311 \times 0.9085

\dfrac{T_o - 293 }{130}= 0.937

T_o - 293= 0.937 \times 130

T_o - 293= 121.81

T_o = 121.81+ 293

T_o = 414.81 \ K

T_o = (414.81 - 273)^0C

T_o = 141.81 ^0C

4 0
4 years ago
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