All categories

3 years ago

Using newtons 2nd law, explain The relationship between acceleration, mass, and force.

1 answer:

8 0

According to Newton's second law of motion, Force is mass times the acceleration of the object.

It would be: F = m*a

Hope this helps!

You might be interested in

What is the current in a wire of radius R = 2.02 mm if the magnitude of the current density is given by (a) Ja = J0r/R and (b) J

Sloan [31]

Explanation:

For this problem we have to take into account the expression

J = I/area = I/(π*r^(2))

By taking I we have

I = π*r^(2)*J

(a)

For Ja = J0r/R the current is not constant in the wire. Hence

$I(r) = \pi r^{2} J(r) = \pi r^{2} J_{0}r/R = \pi r^{3} (3.74*10^{4}A/m^{2})/(2.02*10^{-3}m)$

and on the surface the current is

$I(R) = \pi r^{2} J(R) = \pi r^{2} J_{0}R/R = \pi(2.02*10^{-3})^{2} (3.74*10^{4}) = 0.47 A$

(b)

For Jb = J0(1 - r/R)

$I(r)=\pi r^{2}J(r) =\pi r^{2} J_{0}(1 - r/R)=\pi r^{2}J_{0}(1-\frac{r}{2.02*10^{-3}} )$

and on the surface

$I(R)=\pi r^{2}J_{0}(1-R/R)=\pi r^{2}J_{0}(1-1)= 0$

(c)

Ja maximizes the current density near the wire's surface

Additional point

The total current in the wire is obtained by integrating

$I_{T}=\pi\int\limits^R_0 {r^{2}Ja(r)} \, dr = \pi \frac{J_{0}}{R}\int\limits^R_0 {r^{3}} \ dr =\pi \frac{J_{0}R^{4}}{4R}=\frac{1}{4}\pi J_{0}R^{3}=2.42*10^{-4} A$

and in a simmilar way for Jb

$I_{T}=\pi J_{0} \int\limits^R_0 {r^{2}(1-r/R)} \, dr = \pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2R}]=\pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2}]$

And it is only necessary to replace J0 and R.

I hope this is useful for you

regards

7 0

3 years ago

Where is cloud data stored?

Annette [7]

Answer: i think its local drive

Explanation:

5 0

3 years ago

Read 2 more answers

Are the two expressions equvalent 7(8x+5) and 48x + 35

Evgesh-ka [11]

Yes they are equivalent because 7x5=35 and 8x x 5=48x

4 0

4 years ago

How does a projectile differ from an object in free fall?

VashaNatasha [74]

A projectile has some form of thrust to propel it in the desired direction, while an object in free fall has no extra force guiding/propelling it

8 0

4 years ago

Read 2 more answers

You have a perfectly circular apple pie with a radius of 15cm. You cut the pie into 12 approximately equal slices. What is the a

Sedaia [141]

Answer:

7.85 cm

30 degree

Explanation:

As we know that that the angular displacement in one turn is 360 degree.

As there are 12 parts which are equally divided so the angle turn by each part is

= 360 / 12 = 30 degree

Thus, the angular displacement of each slice is 30 degree.

Radius of pie = 15 cm

Circumference of pie = 2 x 3.14 x 15 = 94.2 cm

Arc length for complete 360 degree = 94.2 cm

Arc length for 30 degree turn = 94.2 x 30 / 360 = 7.85 cm

5 0

4 years ago