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Whitepunk [10]
3 years ago
12

Using newtons 2nd law, explain The relationship between acceleration, mass, and force.

Physics
1 answer:
shtirl [24]3 years ago
8 0
According to Newton's second law of motion, Force is mass times the acceleration of the object.

It would be: F = m*a

Hope this helps!
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What is the current in a wire of radius R = 2.02 mm if the magnitude of the current density is given by (a) Ja = J0r/R and (b) J
Sloan [31]

Explanation:

For this problem we have to take into account the expression

J = I/area = I/(π*r^(2))

By taking I we have

I = π*r^(2)*J

(a)

For Ja = J0r/R the current is not constant in the wire. Hence

I(r) = \pi r^{2} J(r) = \pi r^{2} J_{0}r/R = \pi r^{3} (3.74*10^{4}A/m^{2})/(2.02*10^{-3}m)

and on the surface the current is

I(R) = \pi r^{2} J(R) = \pi r^{2} J_{0}R/R = \pi(2.02*10^{-3})^{2} (3.74*10^{4}) = 0.47 A

(b)

For Jb = J0(1 - r/R)

I(r)=\pi r^{2}J(r) =\pi r^{2} J_{0}(1 - r/R)=\pi r^{2}J_{0}(1-\frac{r}{2.02*10^{-3}} )

and on the surface

I(R)=\pi r^{2}J_{0}(1-R/R)=\pi r^{2}J_{0}(1-1)= 0

(c)

Ja maximizes the current density near the wire's surface

Additional point

The total current in the wire is obtained by integrating

I_{T}=\pi\int\limits^R_0 {r^{2}Ja(r)} \, dr = \pi \frac{J_{0}}{R}\int\limits^R_0 {r^{3}} \ dr =\pi  \frac{J_{0}R^{4}}{4R}=\frac{1}{4}\pi J_{0}R^{3}=2.42*10^{-4} A

and in a simmilar way for Jb

I_{T}=\pi J_{0} \int\limits^R_0 {r^{2}(1-r/R)} \, dr = \pi   J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2R}]=\pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2}]

And it is only necessary to replace J0 and R.

I hope this is useful for you

regards

7 0
3 years ago
Where is cloud data stored?
Annette [7]

Answer: i think its local drive

Explanation:

5 0
3 years ago
Read 2 more answers
Are the two expressions equvalent 7(8x+5) and 48x + 35
Evgesh-ka [11]
Yes they are equivalent because 7x5=35 and 8x x 5=48x
4 0
4 years ago
How does a projectile differ from an object in free fall?
VashaNatasha [74]
A projectile has some form of thrust to propel it in the desired direction, while an object in free fall has no extra force guiding/propelling it

8 0
4 years ago
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You have a perfectly circular apple pie with a radius of 15cm. You cut the pie into 12 approximately equal slices. What is the a
Sedaia [141]

Answer:

7.85 cm

30 degree

Explanation:

As we know that that the angular displacement in one turn is 360 degree.

As there are 12 parts which are equally divided so the angle turn by each part is

= 360 / 12 = 30 degree

Thus, the angular displacement of each slice is 30 degree.

Radius of pie = 15 cm

Circumference of pie = 2 x 3.14 x 15 = 94.2 cm

Arc length for complete 360 degree = 94.2 cm

Arc length for 30 degree turn = 94.2 x 30 / 360 = 7.85 cm

5 0
4 years ago
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