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Alina [70]
3 years ago
13

Q 26.12: Assume current flows in a cylindrical conductor in such a way that the current density increases linearly with radius,

from zero at the center to 1.0 A/m2 at the surface of the conductor. If the conductor has a cross sectional area of 1.0 m2, what can you say about the current in this conductor
Physics
1 answer:
elixir [45]3 years ago
6 0

Answer:

The current is 0.67 A.

Explanation:

Density, J = 1 A/m^2

Area, A = 1 m^2

Let the radius is r. And outer is R.

Use the formula of current density

I = \int J dA = \int J 2\pi r dr\\\\I = \int_{0}^{R}\frac{2\pi r^2}{R} dr\\\\I = \frac{2 \pi R^2}{3}.... (1)Now A = \pi R^2\\\\1 =\pi R^2\\\\R^2 = \frac{1}{\pi}\\\\So, \\\\I = \frac{2\pi}{3}\times \frac{1}{\pi}\\\\I = 0.67 A

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s344n2d4d5 [400]

Answer:

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Explanation:

Plant name:                                    Uses:

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3 0
3 years ago
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Dimas [21]
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Through the process of elimination:
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</span><span>- It makes food for the adult plant. NO. The food of plants in made of green leaves that contain chlorophyll in the process of photosynthesis.
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5 0
3 years ago
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Answer:

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Explanation:

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Answer:

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