Answer:
Explanation:
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In this case, when determining empirical formulas by knowing the by-mass percent, we first must assume the percentages as masses so we can compute the moles of each element:
Now, for the determination of the subscript of each element in the empirical formula, we divide the moles by the fewest moles (P or N):
Thus, the empirical formula is:
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Answer:
7.59°C
Explanation:
Using the formula;
Q = m × c × ∆T
Where;
Q = amount of heat (joules)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to this question;
m = 80g
c = 4.2 J/g°C.
Q = 2550J
∆T = ?
Using Q = m × c × ∆T
∆T = Q/mc
∆T = 2550 ÷ (80 × 4.2)
∆T = 2550 ÷ 336
∆T = 7.589°C
The change in temperature of water = 7.59°C.
Answer:
pH = 0.32
Explanation:
To solve this problem we use the <em>Henderson-Hasselbach equation</em>:
- pH = pKa + log
In this case
- [A⁻] is [NH₃], as it is the conjugate base of a weak acid
- [HA] is [NH₄⁺], as it is a weak acid
So now we just <u>compute the data in the equation</u>
- pH = 9.24 + log
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